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cupoosta [38]
3 years ago
15

£980 is divided between Caroline, Sarah & Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as

much as Gavyn. How much does Sarah get?
Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Sarah has received £ 294

<u><em>Solution:</em></u>

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

<em><u>Caroline gets twice as much as Sarah</u></em>

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

<em><u>Sarah gets three times as much as Gavyn</u></em>

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

<em><u>Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"</u></em>

From eqn 2,

g = \frac{s}{3}  --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294

Thus sarah has received £ 294

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We are given that the students receive different versions of the math namely A, B, C and D.

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So, in percent the probability is 0.0124 × 100 = 1.24%

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