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poizon [28]
4 years ago
14

Please answer a and c

Mathematics
1 answer:
n200080 [17]4 years ago
5 0

add the numbers on both side by 3

4 + 3 = 7

8 + 3 = 11

rewrite the expression

7<11

that is still true

do the same by multiplying it by 2 and rewrite the inequality


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There is a rectangle ABCD, with sides AB = CD = 32, and sides and BC = DA = 24. The rectangle is rotated 90° clockwise about C,
Sphinxa [80]

Answer

given,

side of rectangle, AB = CD = 32

                              BC = DA = 24

rectangle is rotated 90° clockwise about C.

then rotated 90° clockwise about D.

Path traveled by the point A for first rotation will be in circle with radius AC.

   D_1 = \dfrac{\theta_1}{360^0}\times \pi \times {AC}^2

      AC = \sqrt{24^2+32^2}

             AC = 40

             θ₁ = 90°

   D_1 = \dfrac{90^0}{360^0}\times \pi \times {40}^2

         D₁ = 1256.64

For the second rotation Point A will move in circular path with radius of AD

   D_2 = \dfrac{\theta_2}{360^0}\pi {AD}^2

             AD = 24

             θ₁ = 90°

   D_2 = \dfrac{90^0}{360^0}\times \pi \times {24}^2

         D₂ = 452.39

total path traveled by the point A

   D = D₁ + D₂

   D = 1256.64 + 452.39

  D = 1709.03

3 0
3 years ago
PLEASE HELP EASY MATH PLEASE ASAP
Sedbober [7]

Answer:

Step-by-step explanation:

I don't really know what your question is asking for but I can tell you there's a quadratic formula that solves for x-ints. There's a quadratic equation which is Ax + bx + c = 0.

4 0
3 years ago
the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri
Y_Kistochka [10]

The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

  • The function for Option 1 is;  \underline{ f(n) = 1,100 + (n - 1) \cdot 100}
  • The function for Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Reasons:

The given table of values is presented as follows;

\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

  • The amount in dollars after <em>n</em> years, \underline{ f(n) = 1,100 + (n - 1) \cdot 100}

For Option 2, it is possible to find;

1,331 ÷ 1,210 = 1,210 ÷ 1,100 = 1.1

Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

  • The function for the Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Learn more about arithmetic and geometric progression here:

brainly.com/question/8932895

brainly.com/question/22977503

4 0
3 years ago
You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll
Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

b. P (R6| G3)= \frac{1}{3}

c. P(G3|E)=\frac{2}{3}

d. P (E|G3)=\frac{2}{3}

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

6 0
3 years ago
PLEASE HELP! While shopping, Kyla found a dress that she would like to purchase, but it costs $52.25 more than she has. Kyla cha
zhenek [66]
I don’t have a double number line but she would have to spend 9.5 (9 1/2) hours babysitting to earn enough money to buy the dress
7 0
3 years ago
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