All categories

6 months ago

PLEASE PLEASE PLEASE HELP +30 POINTS!

Mathematics

2 answers:

Dmitrij [34]6 months ago

7 0

It is b, d, c, and d

zavuch27 [327]6 months ago

6 0

Answer:

1.option b

2.option c

3.option non (-39/20)

4.option a

Step-by-step explanation:

-7/9 x 3/5

$\frac{ - 7}{9} \times \frac{3}{5} \: \\ (3 \: and \: 9 \: are \: common \: so \: we \: can \: simplify them) \\ \frac{ - 7}{3} \times \frac{1}{5} \\ \frac{ - 7 \times 1}{3 \times 5} = \frac{ - 7}{15}$

You might be interested in

Is this a right triangle??? Show work

podryga [215]

Answer:

This is a right angle.

Step-by-step explanation:

As you can see below, the angle specified is 90 degrees. That is a right angle.

6 0

2 years ago

Please help ...........

viva [34]

I believe the answer is d

7 0

2 years ago

I'll mark brainliest Please help

Ilia_Sergeevich [38]

Answer:

Y=0.1(1.25)^t is growth. Y=426(0.98)^t is decay. Y=100(1-1/2)^t is decay. Y=((1-0.03) 1/2) ^2t is decay. And y=2050(1/2)^t is decay. Hope this helps!

Step-by-step explanation:

5 0

2 years ago

Find the Volume of the cone

Karolina [17]

Answer:

Step-by-step explanation:

first we need to know that redious isn't gien

so we have to find redious

according to Pythagoras theorem

a²+b²=c²

a=√c²-b²

a=17²-15²

a=√(17+15)(17-15)

a=√64

a=8

$as \: we \: khow \: volume \: of \: a \: cone$

$= \frac{1}{3} \pi {r}^{2} h$

$\frac{1}{3} \pi \times {8}^{2} \times 15$

$\frac{\pi}{3} \times 64 \times 15$

$\pi \times 64 \times 5$

$3.141 \times 64 \times 5$

$1005.12$

7 0

2 years ago

a tight roll of paper, as delivered to the printer, is 60cm in diameter, and the paper is wound on to a wooden cylinder 8cm in d

Alekssandra [29.7K]

The area of the paper is the amount of space it occupies.

The length of papers around the edge is 1607680 cm

The given parameters are:

$\mathbf{d_1 = 60cm}$

$\mathbf{d_2 = 60cm + 8cm = 68cm}$

The area of the circle head is:

$\mathbf{Area = \pi \frac{d^2}{4}}$

So, we have:

$\mathbf{Area = \pi \frac{d_2^2 - d_1^2}{4}}$

Substitute known values

$\mathbf{Area = \pi \frac{68^2 - 60^2}{4}}$

$\mathbf{Area = \pi \frac{1024}{4}}$

$\mathbf{Area = 256\pi}$

The length of the paper is then calculated as:

$\mathbf{Length = \frac{Area}{0.0005}}$

This gives

$\mathbf{Length = \frac{256\pi}{0.0005}}$

$\mathbf{Length = \frac{256 \times 3.14}{0.0005}}$

$\mathbf{Length = 1607680}$

Hence, the length of papers around the edge is 1607680 cm