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Serggg [28]
3 years ago
10

For the following system of equations, find the points where F(X)=G(X) by completing

Mathematics
1 answer:
miss Akunina [59]3 years ago
3 0

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if an airplane travels 660 mph how long will it take an airplane to travel to a distance of 2970 miles?
vazorg [7]

Answer:

4 hours and 30 minutes.

Step-by-step explanation:

660 miles = 1 hour
1320 miles = 2 hours
1980 miles = 3 hours
2640 miles = 4 hours

There are only 330 miles left and that is half of 660mph so therefore it would only take half an hour for these last 330 miles.

So we know that it will be taking 4 hours, you would then add the 30 minutes which gives you 4 hours and 30 minutes.

Hope this helps!

4 0
2 years ago
Please I neeed help
Novosadov [1.4K]
The answer is 59049 hope this helps
8 0
3 years ago
Read 2 more answers
Joseph typed a 1200- word essay in 25 minutes.at this rate,determine how many words he can type in 45 minutes.
Deffense [45]
First you divide 1200 by 25 (1200/25) it comes out to 48. 
That means the he types at a rate of 48wpm. So then all you have to do is multiply 48 and 45 and you get 2160 words.
4 0
3 years ago
Please help me with these questions and show how u got them, i will mark you brainliest !
lianna [129]

Answer: 1) 25b   2) ac   3)ba

1) Since b is unknown, your answer will be 25b

2) Since both variables, a and c, are unknown, your answer will be ac

3) Since both are unknown here, it will be ba!

4 0
3 years ago
5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio
kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85°  below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component  Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy =  -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = \sqrt{Vx^{2} + Vy^{2}  }

==> \sqrt{15.83^{2} + 14.79^{2}  } = <em>21.66 knot</em>

<em></em>

direction of boat = tan^{-1} \frac{Vy}{Vx}

==> tan^{-1} \frac{14.79}{15.83} = <em>43.05°</em>

3 0
3 years ago
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