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3 years ago

4162 to 3 significant figures

1 answer:

8 0

Hey there Altagraciasouth :)

Significant Figure Question:

**Question 4162 to 3 SF

Explanation:

We first have to look for the third number in 4162. That would be 62!

So we round 62 to the nearest ten. Which gives us 60!

**Answer: 4160

Hope this helped :)

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The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d

TEA [102]

Answer:

The probability that it would take more than four hours to construct a soapbox derby car = 0.1587 or 15.87 $\%$

Step-by-step explanation:

Given -

Mean $(\nu )$ = 3 hours

Standard deviation $(\sigma )$ = 1 hours

Let X be the no of hours to construct a soapbox derby car

the probability that it would take more than four hours to construct a soapbox derby car =

$P(X > 4)$ = $P(\frac{X - \nu }{\sigma}> \frac{4 - 3 }{1})$

= $P(Z > 1)$ Put $(Z = \frac{X - \nu }{\sigma})$

= 1 - $P(Z < 1)$

= 1 - .8413 Using z table

= 0.1587

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3 years ago

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Answer:

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Step-by-step explanation:

The sampling distribution of a sample statistic is the probability distribution of the population of all possible values of the sample statistic.

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3 years ago

What is the perimter of this figure?

alexira [117]

Answer:

30!

Step-by-step explanation:

Add all sides.

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2 years ago

1 kg = ___ g A : 1 B : 10 C : 100 D : 1,000

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3 years ago

Find the volume of the parallelepiped with adjacent edges t = 3j – 4j – 6k, u = 3i – 7j – 7k and v = 5i + j + 3k.

Assoli18 [71]

Answer:

94 cubic units

Step-by-step explanation:

The volume of this parallelepiped (the product of area of its base and height) is equal to the absolute value of the scalar triple product $|\vec{t}\cdot (\vec{u}\times \vec{v})|$

Since

$\vec{t}=3\vec{i}-4\vec{j}-6\vec{k}=(3,-4,-6)\\ \\\vec{u}=3\vec{i}-7\vec{j}-7\vec{k}=(3,-7,-7)\\ \\\vec{v}=5\vec{i}+\vec{j}+3\vec{k}=(5,1,3)$

we have

$|\vec{t}\cdot (\vec{u}\times \vec{v})|=\left|\left|\begin{array}{ccc}3&-4&-6\\3&-7&-7\\5&1&3\end{array}\right|\right|=|3\cdot (-7)\cdot 3+(-4)\cdot (-7)\cdot 5+3\cdot 1\cdot (-6)-5\cdot (-7)\cdot (-6)-3\cdot (-7)\cdot 1-3\cdot (-4)\cdot 3|=|-63+140-18-210+21+36|=|-94|=94\ un^3.$

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3 years ago