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Illusion [34]
3 years ago
15

Someone please help me with this question please

Mathematics
2 answers:
ycow [4]3 years ago
6 0
A straight line also measures 180 degrees.

If a straight line is 180 degrees, than 148 degrees plus angle ACB must equal 180 degrees because together they make a straight line.

180 = 148 + ACB
ACB = 32 degrees
iris [78.8K]3 years ago
5 0

Answer:

32

Step-by-step explanation:

<em>The ray created by line BC has two </em><u><em>180° sides</em></u><em>. Side </em><em>AC</em><em> intersects this ray and forms two angles. We can find this second angle by subtracting </em><em>148 </em><em>from </em><em>180 </em><em>to get </em><em>32</em><em>.</em>

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How do u turn a fraction into a percent
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You multiply both the numerator and the denominator by the number that you need to multiply the denominator by to equal 100. Then your numerator is the percent.
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3 years ago
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What is the product?<br> (2x-1)(x+4)<br> 2x²-4<br> 0<br> 2x²+4<br> 0<br> 2x² + 7x-4<br> 2x² – 7x-4
vladimir2022 [97]

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

3 0
3 years ago
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Use calculus to find the area of the triangle with the vertices (0, 5), (2, -2), and (5, 1).
guajiro [1.7K]

The area of the triangle with the vertices (0, 5), (2, -2), and (5, 1) by using the calculus is  21 square unit.

We need to find the equation among all possible pairs and then integrate the equations from one co-ordinate to another co-ordinate

Equation of line passing through (0,5) and (2,-2) is

y-5 = [(-2-5)/(2-0)](x-0)

=>y-5 = (-7) /2x

=>y= (-7/2x)+5 -------(eq1)

Equation of line passing through (0,5) and (5,1) is

y-5 = [(1-5) / (5-0)](x-0)

=>y-5 = (-4/5)x

=>y = (-4/5)x+5-------(eq2)

Equation of line passing from (2,-2) and (5,1) is

y-(-2) = [[1 - (-2)] / (5-2)] / (x-2)

=>y+2=(3/3)(x-2)

=>y=x-4--------(eq3)

Now, we use definite integration to find the area between the different equation of line.

So, area enclosed between the equations is given by the

area =\int\limits^5_2[(-4/5)x+5 - (-7/2)x + 5)dx  + \int\limits^5_1[(-4/5)x+5 -(x-4)]dx

=>area=\int\limits^5_2(7/2-4/5)x dx + \int\limits^5_1((-9/5)x+9)dx

Using properties of integration,\int\limits x\, dx=x^{2}/2

=>area=\int\limits^5_2(27/10)x dx + \int\limits^5_1(-9/5)x+9)dx

=>area=([27/10)×[5² - 2²])/2 + [ (-9/5)×(5²-1²) ]/2 +9×(5-1)

=>area=(27/20)×(25-4) + (-9/5)×24+9×4

=>area = (27×21)/20 + (-216)/5+ 36

=>area=(567/20) - (216/5) + 36

=>area= [(567-261×4)+(36×20)]/20

=>area=[(567-864)+720]/20

=>area=423/20

=>area=21 square unit.

Hence, area of triangle is 21 square unit.

To know more about area of triangle, visit here:

brainly.com/question/19305981

#SPJ4

4 0
1 year ago
In need of some major help!!
ollegr [7]

The answer to your question is 4.8 kilometers. Brainliest?

4 0
3 years ago
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On which number line are -3 and it’s opposite shown?
kolbaska11 [484]
The first one, the opposite of any negative number is the same number but positive...and vise versa.
8 0
3 years ago
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