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Olegator [25]
1 year ago
10

Maureen measured a house and its lot and made a scale drawing. The scale she used was

Mathematics
1 answer:
PIT_PIT [208]1 year ago
3 0

The most appropriate choice for unitary method will be given by-

Length of driveway  in the drawing is 3 inch

What is unitary method?

Unitary method is the method in which value of a single unit can be calculated from the value of a multiple unit and value of a multiple unit can be calculated from the value of a single unit.

Sometimes value of single unit is less than value of multiple unit

For example - cost of food and quantity of food

Sometimes value of single unit is more than value of multiple unit

For example- Number of men and time taken by those men to do a work

Here,

Scale used by Maureen is 1 inch = 8ft

Actual length of house's driveway = 24 feet

8 ft of room is equal to 1 inch on scale

1 ft of room is equal to \frac{1}{8} inch on scale

24 feet of room is equal to \frac{1}{8} \times 24 inch on scale

24 feet of room is equal to 3 inch on scale

Length of driveway  in the drawing is 3 inch

To learn more about unitary method, refer to the link-

brainly.com/question/24587372

#SPJ9

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Shelly rolls a number cube labeled from 1 to 6. What is the probability that she rolls a number greater than 5 or less than 2?
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Can someone tell me how
gulaghasi [49]

the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.

multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.

so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5   <----- notice, current coefficient times 3 divided by 4+1.

anyhow, with that out of the way, lemme proceed in this one.

\bf ~~~~~~~~\textit{binomial theorem expansion} \\\\ \qquad \qquad (1+ax)^n\implies \begin{array}{llll} term&coefficient&value\\ \cline{1-3}&\\ 1&+1&(1)^n(ax)^0\\\\ 2&+\frac{(1)(n)}{1}\to n&(1)^{n-1}(ax)^1\\\\ 3&+\frac{n\cdot (n-1)}{2}&(1)^{n-2}(ax)^2 \end{array}

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.

so then, we know that the expanded 2nd term is 24x therefore

\bf n(1)^{n-1}(ax)1 = 24x\implies n(1)(ax)=24x\implies nax=24x\implies n=\cfrac{24}{a}

we also know that the expanded 3rd term is 240x², therefore we can say that

\bf \cfrac{n(n-1)}{2}~~(1)^{n-2}(ax)^2 = 240x^2\implies \cfrac{n(n-1)}{2}(1)(a^2x^2) = 240x^2 \\\\\\ \cfrac{(n^2-n)(a^2x^2)}{2}=240x^2\implies \cfrac{(n^2-n)(a^2)}{2}=\cfrac{240x^2}{x^2}\implies \cfrac{a^2n^2-a^2n}{2}=240 \\\\\\ a^2n^2-a^2n=480

but but but, we know what "n" equals to, recall above, so let's do some quick substitution

\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft

7 0
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