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meriva
3 years ago
10

Find the slope please

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
8 0

Answer:

m= 4/5

Step-by-step explanation:

You have to plug the points into the formula

m =

<u>y2 - y1 </u>

x2 - x1

so it would look like

m=

<u>- 5 - 3 </u>

- 2 -8

m=

<u>- 8</u>

-10

Then you cancle out the negatives and simplify to get m=4/5

sesenic [268]3 years ago
3 0

Answer:

The slope is -4 over -5

Step-by-step explanation:

Your equation should be y2-y1 over x2-x1. At first you will get -8 over -10 then you simplify and get -4 over -5

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y=18(x^2+(1/2)x + 1/16) + 14 - 9/8

y = 18(x + 1/4)^2 + 103/8


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The minimum of the function is the y-value of the vertex, 103/8.
=======================================...

Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.

The correct way of doing what dizzle TRIED to do:

For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)

y=18x^2+9x+14

a = 18
b = 9

- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4

Take that value for x, evaluate function at that value to get y.
=======================================...
Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:

x-intercept(s) can be found by setting function equal to zero and solving:

y = 18(x + 1/4)^2 + 103/8

0 = 18(x + 1/4)^2 + 103/8

18(x + 1/4)^2 = - 103/8

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x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12

These are the roots of the equation f(x) = 0

Since the roots are complex, there are no x-intercepts. The function is entirely above the x-axis. </span>
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