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laila [671]
1 year ago
11

Bacterial cells could have any of the following appendages except

SAT
1 answer:
sesenic [268]1 year ago
5 0

Bacterial cells could have any of the following appendages except cilia. Hence option B is correct.

<h3>What are bacterial cells?</h3>

Bacterial cells are defined as tiny, one-celled creatures. Nearly all areas of the world are home to bacteria, which are essential to its ecosystems.

On certain bacterial species, the flagella, which are locomotional organs, and the pili, which are surface appendages, can be distinguished. Both Gram-positive and Gram-negative bacteria have flagella, and their presence aids in identification.

Thus, bacterial cells could have any of the following appendages except cilia. Hence option B is correct.

To learn more about bacterial cells, refer to the link below:

brainly.com/question/2145627

#SPJ1

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Please help! I need an explanation :(
sp2606 [1]

Answer:

Do you need a full explanation?

Explanation:

8 0
3 years ago
Luminous objects such as flashlights emit light that we can see. How do we see an object that isn’t luminous?
o-na [289]

B is the correct answer.

3 0
3 years ago
Read 2 more answers
During last year's basketball season, Jackson attempted
OLga [1]

This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

150 free throws of which he made

120. So far this season, he's attempted 24 and made 16. A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted. Assuming calculations began with the start of last year's season, which of the following best approximates Jackson's overall free-throw percentage to date?

A. 67%

B. 73%

C. 78%

D. 80%

Answer:

B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

150 free throws of which he made

120

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

= 80%

This season, he's attempted 24 and made 16

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (16÷24) × 100

= 66.67%

Approximately = 67%

The best approximation for Jackson's overall free-throw percentage to date is

(Percent Free Throw for last season + Percent Free Throw for this season) ÷ 2

Percent Free Throw for last season

= 80%

Percent Free Throw for this season = 66.67%

Therefore, (80% + 66.67%) ÷ 2

= 146.67% ÷ 2

= 73.335%

Approximately = 73%

Therefore, Jackson's overall free-throw percentage to date is 73%

6 0
3 years ago
How many phosphate groups does an ATPmolecule have? 1 2 3 4
OverLord2011 [107]

Answer:

They have 3

Explanation:

ATP is a nucleotide consisting of an adenine base attached to a ribose sugar, which is attached to three phosphate groups

Hope this helps (:

3 0
3 years ago
Read 2 more answers
Why... I dislike this site.... I just got a 0/3 on my quiz and I looked up the answers on here and saw one person that had the s
aalyn [17]
Hopefully you can retake your quiz!! :)
8 0
3 years ago
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