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shusha [124]
3 years ago
5

Let’s suppose for a moment, that you are tasked with helping people travel from one location to another without using their own

vehicles. What would be required to make sure that this task is possible. Make a list of different components that would be needed.
What is the name of this system?
SAT
1 answer:
Anni [7]3 years ago
5 0

Answer:

Hey

The name (i think) would be the driving system

You would need

To make sure there is fuel

to ask the person who owns the vehicle if you can drive it

to make sure the vehicle has wheels

to make sure that it isn't going to explode

to make sure its windows role down

to make sure that it has air conditioning

to make sure that there is a radio in the vehicle

to make sure there isn't a wasp in the vehicle

to  make sure there is an Old Mc Donalds nearby

to make sure that the Old Mc Donalds nearby carries your favorite snack

to make sure that the Old Mc Donalds nearby has your passenger's favorite snack.

to make sure that the Old Mc Donalds has your passenger's brother's favorite snack in case wants he comes.

to make sure that the Old Mc Donalds has your passenger's uncle's favorite snack in case wants he comes.

to make sure that the Old Mc Donalds has your passenger's sister's favorite snack in case wants she comes.

to make sure that the Old Mc Donalds has your passenger's other sister's favorite snack in case wants she comes.

to make sure that the Old Mc Donalds has your passenger's whole family's favorite snacks in case they all want to come.

to make sure that there is a place for the vehicle to drive

to make sure that you know where you're going

to make sure that the vehicle won't crash

to make sure that you know how to drive the vehicle

And that is all I can think of. Wait, maybe just one more thing,

to make sure that the Old Mc Donalds has your passenger's brother's friend bill's favorite snack in case wants he comes.

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Which of these are good ways to find a buyer’s agent? select all that apply
Gre4nikov [31]

The ways to find a buyer's agent include all of the following:

  • Referrals
  • Search online
  • Interview agents

<h3>Who is a Buyer's Agent?</h3>

A buyer's agent can be described as a real estate professional that guides a buyer when making a purchase of a home.

The duty of a buyer's agent is to ensure the buyer gets the best deal and also protest the buyer's interest.

Thus, getting referrals from people who have used trusted buyer's agent is a good way to find a good buyer's agent. Also, you can search online and/or interview agents to get the best one.

Therefore, the ways to find a buyer's agent include all of the following:

  • Referrals
  • Search online
  • Interview agents

Learn more about buyer's agent on:

brainly.com/question/26181665

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2 years ago
Do I have std please tell me
Marina86 [1]

Answer:

yes

Explanation:

yes

5 0
3 years ago
Read 2 more answers
A global resources company uses data-intensive, cloud-based simulation software, but users in remote locations find that the res
umka2103 [35]

The type of technology illustrated in the given example is called; Edge Computing

The correct answer to the question is Edge Computing. This is because Edge computing, is a type of technology that brings computation and data storage closer to the devices that will receive it.

This way of operation of edge computing described above is way better than the other way of relying on a central location that may be so far away from the device to use it.

Now, the system above is done to make sure that real-time data, does not suffer from latency issues which could be responsible for a degrade in performance of applications.

Read more on Edge Computing at; brainly.com/question/23858023

4 0
2 years ago
A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t
OLga [1]

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 \frac{m}{s}.

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f1=f\frac{v+-vR}{v+-vE}

Where:

  1. f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  2. v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
  3. vR, vE: Speed ​​of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
  4. ±, ∓:
  • We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

  • We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

  • f1= 30,000 Hz + 900 Hz= 30,900 Hz
  • f= 30,000 Hz
  • v= 340 m/s
  • vE=vR= vbat
  • Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

Solving:

\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03×( 340\frac{m}{s} -vbat)= 340 \frac{m}{s} + vbat

1.03×340\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 340 \frac{m}{s}= vbat + 1.03×vbat

10.2 \frac{m}{s}= 2.03×vbat

10.2 \frac{m}{s}÷ 2.03 = vbat

<u><em>5.02 </em></u>\frac{m}{s}<u><em>= vbat</em></u>

In summary, the speed of the bat is closest to 5.02 \frac{m}{s}.

Learn more about the Doppler effect:

  • brainly.com/question/17107808
  • brainly.com/question/14929897
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2 years ago
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Elodia [21]
C. Knowing and understanding what to teach
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