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TiliK225 [7]
1 year ago
12

I need help please!!!

Mathematics
1 answer:
myrzilka [38]1 year ago
5 0

the slope of the given point is m=−3/4

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A famous basketball player scored 97 points in a high scool game, breaking a national record. She made 43 more 2-point baskets t
ziro4ka [17]
X - 3pt  baskets  (he reaches 3x points)
y - 2pt baskets  (he reaches 2y points)

We know, that  y=x+43

97 - 1 free throw = 97 - 1 = 96
Sum of points:  96

3x + 2y = 96.   Substitute  to "y"  an expression "x+43" :

3x + 2(x+43)=96
3x+2x+86=96
5x=10    |:5
x=2 

So y=x+43=2+43=45 

He has made 2  three points baskets and 45 two points baskets
8 0
3 years ago
Can someone pls help with this
Anon25 [30]

Answer:

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7 0
3 years ago
Refer to Table 20-3.A
schepotkina [342]

Answer:

A. 60 Percent

Step-by-step explanation:

Quintle means 5.

Below $69,000 covers three of the five quntiles (bottom, second, and middle).

3/5 equals .6 or 60%

4 0
3 years ago
-8x -12=2(-4x-6) help me solve this using pemdas
Morgarella [4.7K]
So you would simplify scence you cant subtract simplify the variables then do your normal steps of pemdas

6 0
4 years ago
Let n1=50​, X1=10​, n2=50​, and X2=30. Complete parts​ (a) and​ (b) below. a. At the 0.10 level of​ significance, is there evide
iren2701 [21]

Answer:

|Z| = |-4.089| > 1.645 at 0.10 level of significance

Null hypothesis is rejected at  0.10 level of significance

<em>There is a difference between the two Population proportions</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given first sample size (n₁)  = 50

Given  proportion of the first sample p⁻₁= 0.2

Given second sample size (n₂)  = 50

Given proportion of the second sample p₂⁻ = 30/50 = 0.6

<em>Null Hypothesis : H₀: p₁⁻=p₂⁻</em>

<em>Alternative Hypothesis : H₁: p₁⁻≠p₂⁻</em>

<u><em>Step(ii):-</em></u>

Z-statistic

             Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } +\frac{1}{n_{2}) } } }

Where

         P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1} +n_{2} }

        P = \frac{50X0.2+50X0.6}{50+50} = 0.4

<em>Z-statistic</em>

       

      Z = \frac{0.2-0.6}{\sqrt{0.4 X 0.6(\frac{1}{50}+\frac{1}{50}  } }

     Z =  -4.089

Level of significance =0.10

Z₀.₁₀ = 1.645

|Z| = |-4.089| > 1.645 at 0.10 level of significance

Null hypothesis is rejected at  0.10 level of significance

<u><em>Final answer</em></u>:-

<em>There is a difference between the two Population proportions</em>

   

     

       

3 0
3 years ago
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