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Serggg [28]
1 year ago
10

Which ordered pairs are in the solution set of the system of linear inequalities?y2-~xy<%x+1O (5,-2), (3, 1), (-4, 2)O (5, -2

), (3, -1), (4, -3)O (5, -2), (3, 1), (4, 2)O (5, -2), (-3, 1), (4, 2)
Mathematics
1 answer:
Usimov [2.4K]1 year ago
6 0

Ok, so:

We have the following system of linear inequalities:

To solve this system, the answer is really simple:

"Solving" systems of linear inequalities means "graphing each individual inequality, and then finding the overlaps of the various solutions". So, we're going to graph each inequality, and then find the overlapping portions of the solution regions.

In this case, we got the graph, so, we're going to analyze it.

We have these two lines:

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Which number is greater tha 9/4​
Naddika [18.5K]

Answer:

9

Step-by-step explanation:

the biggest number gets eaten by the alligator

5 0
3 years ago
The curved surface area of a right circular cylinder of height 14 cm is 88 cm². ​
Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

  • ➣ Height of cylinder = 14 cm
  • ➣ Curved surface area = 88 cm²

\begin{gathered}\end{gathered}

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

  • ➠ Radius of cylinder
  • ➠ Diameter of cylinder

\begin{gathered}\end{gathered}

<u>USING</u><u> </u><u>FORMULAS</u> :

\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}

\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}

  • ➛ Csa = Curved surface area
  • ➛ π = 22/7
  • ➛ r = radius
  • ➛ h = height
  • ➛ d = diameter

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\  \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}}  \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times  \cancel{ 14}}}}  \\  \\  \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\  \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\  \\ \qquad{\longrightarrow{\sf{r =  \frac{88}{88}}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\  \\  \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}

Hence, the diameter of the base of the cylinder is 2 cm.

\rule{300}{2.5}

3 0
2 years ago
Read 2 more answers
Factor 5v^2 - 23v - 10​
AfilCa [17]

Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

ac  = -50

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

  • 5v^2 - 23v - 10
  • 5v^2 - 25v + 2v - 10
  • 5v(v - 5) +2(v -5 )
  • (5v + 2)(v - 5)

The factored expression is (5v + 2)(v - 5)

7 0
2 years ago
Please could I have some help :)
nirvana33 [79]

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

5 0
3 years ago
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Adult tickets for the school musical sold for $3.50 and students tickets sold for $2.50. 321 tickets were sold altogether for $9
Licemer1 [7]
186 student tickests were sold and 135 adult tickets were sold

4 0
3 years ago
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