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2 years ago

In negative control, what molecule would you expect to find bound to the operator if there is no transcription?.

Chemistry

1 answer:

Fofino [41]2 years ago

3 0

A repressor is found if there is no transcription.

What is the function of a repressor?

A protein that prevents the expression of one or more genes is known as a repressor in the context of genomics. The repressor protein inhibits the synthesis of messenger RNA by attaching to the promoter region of the gene(s) (mRNA). The control of gene expression in cells requires repressor proteins.

A DNA fragment is copied into RNA during transcription. Messenger RNA is the term for DNA segments that are translated into RNA molecules that can encode proteins. Non-coding RNAs are RNA molecules that contain copies of other DNA sequences. Only 1% to 3% of all RNA samples are mRNA.

Hence, the answer is the presence of repressor protein.

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Oceanic crust

ludmilkaskok [199]

Answer: It would be C

7 0

3 years ago

C’est quoi homogène

Anettt [7]

What is homogeneous?

A homogeneous mixture is a solid, liquid, or gaseous mixture that has the same proportions of its components throughout any given sample.

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4 years ago

30 mL of 0.25 M acetic acid are titrated with 0.05 M KOH. What is the pH after addition of 75 mL KOH? Group of answer choices

hjlf

Answer:

The PH of the mixture is 4.74

Explanation:

The number of millimoles of acetic acid is calculated using the formula:

No of millimoles= Molarity * Volume( in ml)

= 0.25M * 30ml = 7.5 moles

Number of millimoles of KOH is calculated using:

Number of millimoles = Molarity * Volume ( in ml)

=0.05M * 75ml

= 3.75 moles

The PH of the solution is derived using:

pH = pKa + log [salt] / acid

= $-log [ 1.8 * 10^5 ] + log [ 3.75 mmoles/ 3.75 mmoles]$

=4.74

5 0

4 years ago

You want to know how much total energy is required to operate a 100-watt light bulb. do you need any more information?

vampirchik [111]

Yes; you need to know how long the light bulb is on.

<h3>How much electricity does a light bulb use?</h3>

Because of this, lower wattage bulbs are sometimes referred to as "equivalent to 60W"; nevertheless, what is equal is brightness, not energy consumption.

Converting wattage to kilowatts is the best way to determine how much energy your lightbulb consumes. Thus, 0.1 kW would be needed per hour for a 100W light bulb.

Incandescent (up to 100W) and halogen (up to 120W) light bulbs with higher energy consumption are being phased out. You may get ornamental exposed carbon filament light bulbs, which are normally 40–60W, if you still have any of them operating in your house.

To learn more about electricity from given link

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4 0

2 years ago

In the first step of the Ostwald process for the synthesis of nitric acid, ammonia is converted to nitric oxide by the high-temp

Paul [167]

Solution: The given balanced equation is:

$4NH_3+5O_2\rightarrow 4NO+6H_2O$

If we have a hypothetical equation:

$A+2B\rightarrow 3C+5D$

Then the rate could be written as:

$rate=-\frac{\Delta [A]}{\Delta t}=-\frac{1}{2}\frac{\Delta [B]}{\Delta t}=\frac{1}{3}\frac{\Delta [C]}{\Delta t}=\frac{1}{5}\frac{\Delta [D]}{\Delta t}$

From above expression one thing could easily be noticed that the coefficients of all are inverted. Also, there is negative sign in front of reactants and positive sign in front of the products. Negative sign stands for rate of consumption where as positive sign stands for rate of formation.

Like the above example, we can write the rate for the given equation and it would be looking as:

$rate=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}=-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}$

Now we can easily answer all the parts of the question.

(a) From above expression, the rate of consumption of $O_2$ related to rate of consumption of $NH_3$ as:

$-\frac{1}{5}\frac{\Delta [O_2]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

multiply both sides by -5

$\frac{\Delta [O_2]}{\Delta t}=\frac{5}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, rate of consumption of oxygen is $\frac{5}{4}$ the rate of consumption of ammonia.

(b) The relationship between rate of formation of NO to the rate of consumption of ammonia will be written as:

$\frac{1}{4}\frac{\Delta [NO]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 4

$\frac{\Delta [NO]}{\Delta t}=-\frac{\Delta [NH_3]}{\Delta t}$

So, rate of formation of NO equals to the rate of consumption of ammonia.

Now, the rate of formation of $H_2O$ to the rate of consumption of ammonia would be:

$\frac{1}{6}\frac{\Delta [H_2O]}{\Delta t}=-\frac{1}{4}\frac{\Delta [NH_3]}{\Delta t}$

Multiply both sides by 6

$\frac{\Delta [H_2O]}{\Delta t}=-\frac{6}{4}\frac{\Delta [NH_3]}{\Delta t}$

So, the rate of formation of $H_2O$ is $\frac{6}{4}$ times that is 1.5 times to the rate of consumption of ammonia.

5 0

4 years ago