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kozerog [31]
1 year ago
7

The paintings are approximately blank years old round to the nearest integer.

Mathematics
1 answer:
ExtremeBDS [4]1 year ago
5 0

Answer:

16,249 years old

Explanation:

The exponential decay model for carbon-14 is given below:

A=A_0e^{-0.000121t}

The paint contained 14% of the original carbon-14.

• A=14% = 0.14

,

• Ao = 100% = 1

\begin{gathered} 0.14=e^{-0.000121t} \\ \text{ Take the ln of both sides} \\ ln(0.14)=ln(e^{-0.000121t}) \\ ln(0.14)=-0.000121t \\ \text{ Divide both sides by -0.000121} \\ t=\frac{ln(0.14)}{-0.000121} \\ t=16248.9 \\ t\approx16,249 \end{gathered}

The paintings are approximately 16,249 years old.

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What is the measure of ∠L?
otez555 [7]
<h3>Answer:  72.54</h3>

====================================================

Explanation:

We set up a cosine ratio, since we want to connect the adjacent and hypotenuse. Then we'll use the inverse cosine, which is also known as arccosine, to isolate the angle value.

This is what your steps could look like:

cos(angle) = adjacent/hypotenuse

cos(L) = LM/LN

cos(L) = 18/60

cos(L) = 0.3

L = arccos(0.3)

L = 72.542396876278 which is approximate

L = 72.54 degrees approximately

Make sure your calculator is in degree mode.

8 0
2 years ago
I need help answering this ASAP
Nata [24]

Answer:

"D"

if you multiply by Conjugate

the denominator would end up A^2 - b^2

the answer has 25 - 10x

that is D

Step-by-step explanation:

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2 years ago
A rectangular billboard image is 5 ft wide and 4 ft high. If the available billboard space is 25 ft by 15 ft, what are the dimen
Lapatulllka [165]

Answer:

18¾ ft × 15 ft

Step-by-step explanation:

The dimensions of the billboard are 25 ft by 15 ft.

The dimensions of the image are 5 ft by 4 ft  

Case 1.<em> Expand the length of the image to 25 ft. </em>

We have multiplied the length by five, so we must multiply the width by five.

w = 5 × 4 = 20 ft. That's too big. The image will overflow the billboard

by 5 ft.


<em>Case 2. </em><em>Expand the width of the image to 15 ft. </em>

We have multiplied the width by 15/4, so we must multiply the length by 15/4.

l = 15/4 × 5 = 75/4 = . That will fit, with 6¼ ft left over.

The expanded image will be 18¾ ft × 15 ft.

In the image below, the big rectangle represents the billboard, and the red rectangle represents the original image.

The pink rectangle represents the dilation of the original image to a width of 15 ft.

5 0
3 years ago
The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

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6 0
3 years ago
9. Water is added to two containers for 16 minutes. The equations below model the ounces of
Vladimir [108]

The two containers hold 328 ounces at the they hold same amount of water.

<u>Step-by-step explanation:</u>

The equations below model the ounces of  water, y, in each container after x minutes.

y = 16x + 104

y = -2x^{2} +40x+160

At the time after the start when the containers hold  the same amount of water, the two equations must be equal.

⇒ 16 x + 104 = -2x^{2}  + 40 x + 160

The first step is to divide everything by 2 to make it simplified.

⇒ 8 x + 52 = - x^2 +20 x + 80

Now put everything on the left .

x^2 + 8 x - 20 x + 52 - 80 = 0

Add the like terms together to further reduce the equation

x^2 - 12 x - 28 = 0

Factorizing the equation to find the roots of the equation.

Here, b = -12 and c = -28

where,

  • b is the sum of the roots ⇒ -14 + 2 = -12
  • c is the product of the roots ⇒ -14 × 2 = -28
  • Therefore, (x-14) (x+2) = 0
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Take x = 14  and substitute in any of the given two equations,

⇒ y = 16(14) + 104

⇒ y =224+104

⇒ 328 ounces

∴ The two containers hold 328 ounces at the they hold same amount of water.

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