Answer:
The possible parking lengths are 45.96 feet and 174.031 feet
Step-by-step explanation:
Let x be the length of rectangular plot and y be the breadth of rectangular plot
A rectangular parking lot must have a perimeter of 440 feet
Perimeter of rectangular plot =2(l+b)=2(x+y)=440
2(x+y)=440
x+y=220
y=220-x
We are also given that an area of at least 8000 square feet.
So, 
So,

So,
General quadratic equation : 
Formula : 

So, The possible parking lengths are 45.96 feet and 174.031 feet
I believe it’s 16/21 but I’m not sure.