ABCD is a parallelogram. If ad = 2x + 10 and CD = 4x - 20, for what value of x will abcd be a rhombus

A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A

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Answer:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=6.5$ represent the sample mean for Atlanta

$\bar X_{2}=6.7$ represent the sample mean for Chicago

$s_{1}=0.5$ represent the sample deviation for Atlanta

$s_{2}=0.7$ represent the sample standard deviation for Chicago

$n_{1}=100$ sample size for the group Atlanta

$n_{2}=110$ sample size for the group Chicago

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

3 0

3 years ago

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Can someone explain this to me please will give brainliest

KATRIN_1 [288]

The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.

3 0

3 years ago

Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax

zysi [14]

Answer:

Step-by-step explanation:

a. Money held by individuals in savings accounts is part of the M2 money supply, but not part ofthe M1 money supply. Therefore, when Jane withdraws $500 cash from her savings account,the M1 money supply increases by $500. However, the M2 money supply does not changebecause the M1 money supply is included as part of the M2 money supply.b. Money held by banks and governments is not included as part of the money supply. Therefore,when Jane uses $300 to pay her income tax to the U.S. Treasury, that total of $300 is taken out ofboth the M1 and M2 money supplies. When Jane deposits the remaining cash ($80) into hersavings account, the M1 money supply is reduced by that amount, but it does not affect the M2money supply. Therefore, Jane's actions cause the M2 money supply to change by $300 (theamount used to pay her taxes) and the M1 money supply to change by $380 (the amount used topay her taxes plus the amount that was deposited into her savings account). Note that it does notmatter that Jane no longer has the $120 she used to pay for the gold clubs, as the funds remainsin someone else's checking account. So this amount is neither removed from the M1 moneysupply nor the M2 money supply.NumericResponseDifficulty: 03 HardLearning Objective: 1402 List anddescribe the components of the U.S.money supply.5000380300References

5 0

3 years ago

What is 90 divided by 12???? <br> pls help i need to get my grades up

Andrew [12]

Answer:

7.5

Step-by-step explanation:

cant u just g oogle it?

5 0

3 years ago

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R=8 P=7 R+P= PLZ im stuck <br>

mihalych1998 [28]

Answer:

15

Step-by-step explanation:

The equation is just a plug in and solve. you have your given variables and all you have to do it plug them into the matching spot and solve

R=8 P=7

8+7=15

7 0

3 years ago