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Simora [160]
3 years ago
9

About how many kilometers are in 0.5 light-years?

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

there are 9461000000000 kilometers in a light year, aka 9.5 trillion

divide it by 2, you get 4730500000000

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Bill booked a ride to the airport. If it rains, the traffic will be bad and the probability that he will miss his flight is 0.06
kvasek [131]

Answer:0.614

Step-by-step explanation:

Given

Probability he will miss flight if it rains=0.06

Probability he will miss flight it does not rain=0.01

Given the probability of rain=0.21

Therefore Probability that it will not rain=1-0.21=0.79

Probability that he will miss the flight =0.21\times 0.06+0.79\times 0.01=0.0205

P(actual raining and he missed the flight| he miss the flight)=\frac{0.21\times 0.06}{0.21\times 0.06+0.79\times 0.01}

=\frac{0.0126}{0.0205}=0.614

7 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
1.3485 divided by 0.31 please
levacccp [35]
The Answer Is 4.35. Hope This Helps.
6 0
3 years ago
Read 2 more answers
The product of nine and a number is added to six the result is 24 what is the number
Andru [333]
Hello!

We can make an equation based on what we know

The product of 9 and a number is

9 * x

Added to six

9 * x + 6

Gives the result of 24

9 * x + 6 = 24

Now you solve it algebraically

Subtract 6 from both sides

9 * x = 18

Divide both sides by 9

x = 2

The answer is 2

Hope this helps!
8 0
3 years ago
73 ÷ 6 = ?<br>(help...)​
mafiozo [28]

Answer:

12.16 it's a continues answer tho

5 0
3 years ago
Read 2 more answers
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