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victus00 [196]
3 years ago
9

The quadrilaterals jklm and pqrs are similar find the length xbof ow

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Since you decided not to let us see the picture, we have no idea what 'ow' is,
or if it's even on the same planet as the quadrilaterals. 

We know absolutely nothing about it, so there's no way to find its length.

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Solve the system of equations.in this form: (x, y)<br><br> -5y + 8x = -18<br><br> 5y + 2x = 58
Gre4nikov [31]
If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
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Given: 2x + 3y= 6. When xhas a value of zero, the y value is 2. true or false<br>​
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What is the distance between point A and point B? Enter your answer in the box.
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Select the correct answer from each drop-down menu.
olganol [36]

The system of inequalities is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

(30, 90) is not a solution of that system, while (60, 160) is a solution.

<h3>How to get the system of inequalities?</h3>

We know that the revenue y is given by:

y ≤ -0.05x^2 + 6x

And we know that the costs are 1.5x + 45, and the revenue must be larger than that, so we also have the inequality:

y >  1.5x + 45

So the system is:

y ≤ -0.05*x^2 + 6x

y >  1.5x + 45

Now, the point (30, 90) means that we need to replace x by 30 and y by 90, replacing that in the second inequality, we will get:

90 > 1.5*30 + 45 = 90

90 > 90

This is false, so the point is not a solution of this inequality, meaning that the point is not a solution of the system.

For the second point we do the same: x= 60, y = 160, replacing that in the second inequality we get:

160 > 1.5*60 + 45 = 135

160 > 135

This is true, now we need to check with the other inequality.

160 ≤  -0.05*60^2 + 6*60 = 180

This is also true.

So the point (60, 160) is a solution to the system.

If you want to learn more about systems of inequalities, you can read:

brainly.com/question/9774970

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