All categories

1 year ago

which scatterplot shows a strong association between two variables even though the correlation is probably near zero?

1 answer:

5 0

The scatterplot that shows a strong association between two variables even if the correlation is near zero is graph C.

<h3>What is zero correlation?</h3>

Correlation is a measure that is used in statistics to measure the linear relationship that exists between two variables.

Zero correlation is when there is no linear relationship between the variables been studied. When it is shown on a graph, zero correlation would have no clear linear trend either positive or negative. A linear trend is roughly a straight line. A linear trend is positive if it slopes upward and negative if it slopes downward.

Please find attached the complete question. To learn more about correlation, please check: brainly.com/question/27246345

#SPJ1

You might be interested in

Help me solve this problem please

lilavasa [31]

Her mother did not gave her enough money.
each pound of bananas costs 80 cents. 5 pounds of that is $0.8 x 5 = $4.00
each pound of apples costs $1.40. 5 pounds of that is $1.40 x 5 = $7.00
$4.00 + $7.00 = $11.00
Therefore, she needs 11 dollars to buy 5 pounds of each bananas and apples. She needs to ask her mother for 1 more dollar.

5 0

3 years ago

Katelyn went to the store and bought 2 shirts that were originally $12 each, but got a 15% discount for each shirt. If she has t

maw [93]

Answer:

Step-by-step explanation:

$21.83

hope this helps :))

3 0

2 years ago

Read 2 more answers

If f(x) = x and g(x) = 2x + 7, what is<br>f[90X)] when g(x) = 11?

kumpel [21]

$\bf \begin{cases} f(x) = x\\ g(x) = 2x+7 \end{cases}~\hspace{7em}g(x)=11\implies \stackrel{g(x)}{11}=2x+7 \\\\\\ 4=2x\implies \cfrac{4}{2}=x\implies \implies \boxed{2=x} \\\\[-0.35em] ~\dotfill\\\\ f[90x]\implies f\left[90\left( \boxed{2} \right)\right]\implies f(180)=\stackrel{x}{180}$

8 0

3 years ago

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

2 years ago

She has read 1/5 of the book already what fraction of the book does she need to read now?

arlik [135]

Answer:

4/5

Step-by-step explanation:

1-1/5=4/5

she still has 4/5 to read

7 0

3 years ago