Answer
5.96046448×10^16
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) 2x -y = 1 -------1
3x - y = -6 ------2
Subtract eqn 2 from eqn 1
-x = 1--6 = 7
x = -7
Put x= -7 in eqn 1
2*-7-y = 1
-14-y = 1
- y = 15
y = -15
2) 4x +2y = 10------1
y = 4x + 2--------2
Put eqn 2 in eqn 1
4x + 2 ( 4x+ 2) = 10
4x + 8x + 4 = 10
12x = 6
x = 6/12 = 1/2
Put x = 1/2 in eqn 2
y = 4* 1/2 + 2= 2 + 2
= 4
3) 6x - y = 2------1
y = 3x + 4---------2
Put eqn 2 in eqn 1
6x - (3x +4) = 2
6x - 3x - 4 = 2
3x = 6
x = 2
y = 3*2 + 4 = 6 + 4
= 10
Here is the compound interest formula solved for years:
<span>Years = {log(total) -log(Principal)} ÷ log(1 + rate)
</span>Years = {log(800) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.903089987 -2.7781512504} / 0.010723865392
</span>Years = {
<span>
<span>
<span>
0.1249387366
} / </span></span></span><span><span><span>0.010723865392
</span>
</span>
</span>
Years =
<span>
<span>
<span>
11.6505319708
</span>
</span>
</span>
That's how many years it takes for the $600 to become exactly $800.00
The question specifically asks how long for the money to be MORE than $800.00?
So, if we enter 800.01 into the equation, then the answer is
Years = {log(800.01) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.9030954156 -2.7781512504} / 0.010723865392
</span>Years =
<span>
<span>
<span>
0.1249441652
</span>
</span>
</span>
/ 0.010723865392
<span>
<span>
<span>
Years = 11.6510381875
</span>
</span>
</span>
<span><span> </span></span>
Answer:
i think its 4 packages
Step-by-step explanation:each package is 25 so if you get 2 its 50 + another package would be 75 so you need one more.
hope this helps
Answer: yes
Step-by-step explanation:
