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Alex17521 [72]
1 year ago
5

The power output of a certain public-address speaker is 6.00W . Suppose it broadcasts equally in all directions.(b) At what dist

ance from the speaker would the sound be barely audible?
Physics
1 answer:
Tems11 [23]1 year ago
6 0

The distance from the speaker would the sound be barely audible is 477.46km.

<h3>What is distance?</h3>

It's how far away two objects or locations are measured numerically as distance. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over"). Sometimes the symbol |AB| is used to indicate how far apart two points are. "Distance from A to B" and "Distance from B to A" are typically equivalent terms. A distance function or metric in mathematics is an extension of the idea of physical distance; it defines what it means for components in a space to be "near to" or "far away" from one another. Distance is a non-numerical unit of measurement in the social sciences and psychology.

Explanation:

Sound audible(barely) = 0dB

I= 10.709*I/10^{-10}=0

I= 10^{-12}*10^{0}=10^{-12}w/m^{2}

distance(r)=\sqrt[]{\frac{P}{4\pi I} } =\sqrt[]{\frac{6}{4\pi * 10^{-12} } } =477.46 km

To learn more about distance ,visit:

brainly.com/question/15172156

#SPJ4

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Gravitational force on the moon is only 1/6 that of the gravitational force on earth. what would be the weight of a 10-kg object
MA_775_DIABLO [31]
According to Newton's Second Law of Motion, the force is equal to the mass of an object multiplied by its acceleration. When you talk about gravitational force, the acceleration referred to here is the acceleration due to gravity. This is very familiar to us in physics. The acceleration due to gravity on Earth is equal to 9.81 m/s². It actually depends on the location. According to the Universal Law of Gravitation:

F = Gm₁m₂/d²

The force is a factor of the product of two masses and their distance from each other. The G is a constant called the universal gravitational constants. So, gravitational force is actually a relative force exerted by one body to another. 

Going back the Second Law of Motion, we can modify the equation to:

F = mg

Since it is mentioned that the gravity on the moon is only 1/6 of the Earth, then the gravity for moon is:
g,moon = 1/6(9.81) = 1.635 m/s²
So, let's compare the weight of the object with a mass of 10 kg. The weight is actually the force due to gravity pulling you towards the center of the body.

Weight on Earth = (10 kg)(9.81 m/s²) = 98.1 N
Weight on Moon = (10 kg)(1.635 m/s²) = 16.35 N

The mass, on the other hand, is not affected by gravity. It is always constant. Therefore, the mass of the object on the moon is the same with its mass on the Earth.
6 0
4 years ago
How does the mass of a satellite, moon or asteroid affect its orbital speed?
sesenic [268]
It would be B, the greater the mass, the more fast the orbiting object will move
7 0
3 years ago
Explain how the basic units are combined to give the derived units of force, velocity and pressure and work​
Lorico [155]

#Force

\\ \sf\longmapsto Force=Mass\times Acceleration

\\ \sf\longmapsto Force=kg m/s^2

\\ \sf\longmapsto Force=Newton (N)

#Velocity

\\ \sf\longmapsto Velocity=\dfrac{Displacement}{time}

\\ \sf\longmapsto Velocity=m/s

#Work

\\ \sf\longmapsto Work=Force\times Displacement

\\ \sf\longmapsto Work=Nm

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3 years ago
As shown in (Figure 1), a layer of water covers a slab of material X in a beaker. A ray of light traveling upwards follows the p
Vsevolod [243]

Answer: the index of refraction of material X will be 1.09 and the angle the light makes with the normal in the air is 81.25°.

Explanation: To find the answer, we need to know the Snell's law.

<h3>What is Snell's law of refraction? Using this, how to solve the problem?</h3>
  • The Snell's law for refraction can be written as,

                      \frac{sin (i)}{sin(r)} =\frac{n_r}{n_i}

where, i is the incident angle, r is the refracted angle, n is the refractive index.

  • As we know that the refractive index of water is 1.33
  • For the first case, incident angle from the picture is 65°, and the refracted angle is 48°. Thus, the refractive index of the medium X will be,

                           \frac{sin 65}{sin48} =\frac{n_w}{n_X} \\n_X=\frac{1.33*sin48}{sin65} =1.09\\

  • In the second case, incident angle is 48° and we have to find the refracted angle r for the air.
  • As we know that the refractive index of air is 1.
  • Thus, the refracted angle will be,

                         \frac{sin 48}{sin r}=\frac{1}{1.33} \\\\ sin(r)=\frac{1.33*sin 48}{1}=0.988\\\\r=sin^{-1}(0.988)=81.25 degrees.

Thus, we can conclude that, the index of refraction of material X will be 1.09 and the angle the light makes with the normal in the air is 81.25°.

Learn more about the Snell's law here:

brainly.com/question/28108530

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3 0
2 years ago
Read 2 more answers
The fire department arrive to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away. H
ipn [44]

Answer: The speed is 4 meters per second or 4 m/s.

Explanation:

First, we have the relationship:

Speed = Distance/Time.

In this case, we know that the fire department arrives to a fire in 210 seconds after leaving the fire station to the burning building which is 840m away, this means that:

Time = 210 seconds

Distance traveled in that time = 840m.

Then the speed is:

Speed = 840m/210s = 4 m/s.

The speed is 4 meters per second.

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