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3 years ago

What occurs when an object travels in a curved path

1 answer:

7 0

<span>When an object travels in a curved path, there must be a force acting toward the center of the circular trajectory. This force is called "centripetal force", and it cause an acceleration of the object, called "centripetal acceleration". The effect of this acceleration is that the velocity of the object changes in direction: however if the circular motion is uniform, the speed (=the magnitude of the velocity) does not change. In this case, the magnitude of the centripetal force is given by
</span> $F=m \frac{v^2}{r}$ <span>
where m is the mass of the object, v its velocity, and r the radius of the circular path.</span>

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Which scientific term is defined as the rate at which work is accomplished?

Oliga [24]

Power is the scientific term defined as the rate at which work is accomplished. Power can be seen everywhere as it is applied to our everyday living. Power is seen when one pushes a heavy cart. It could be seen when a baseball hitter hits the ball.

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3 years ago

An alpha particle (Î±), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elec

vaieri [72.5K]

Answer:

Speed = 575 m/s

Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.

Explanation:

Given :

Potential difference, U = $-3.45 \times 10^{-3} \ V$

Mass of the alpha particle, $m_{\alpha} = 6.68 \times 10^{-27} \ kg$

Charge of the alpha particle is, $q_{\alpha} = 3.20 \times 10^{-19} \ C$

So the potential difference for the alpha particle when it is accelerated through the potential difference is

$U=\Delta Vq_{\alpha}$

And the kinetic energy gained by the alpha particle is

$K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2$

From the law of conservation of energy, we get

$K.E. = U$

$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$

$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$

$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$

$v_{\alpha} \approx 575 \ m/s$

The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

-- magnetic forces

-- gravitational forces

5 0

3 years ago

Calculate change in height of a 2kg ball moving a speed of 10m/s up a frictionless ramp until it stops

Nataliya [291]

The change in the height of the object is 5.1 m.

<h3>Conservation of mechanical energy</h3>

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;

P.E = K.E

$mg \Delta h = \frac{1}{2} mv^2\\\\g \Delta h = \frac{1}{2}v^2\\\\\Delta h = \frac{v^2}{2g} \\\\\Delta h = \frac{(10)^2}{2(9.8)} \\\\\Delta h = 5.1 \ m$

Thus, the change in the height of the object is 5.1 m.

Learn more about conservation of mechanical energy here: brainly.com/question/6852965

6 0

2 years ago

How do physicists distinguish one type of electromagnetic wave from another?

GenaCL600 [577]

A wave is characterized by the cyclic occurrences of crests and troughs. Wavelengthis defined as the distance between two consecutive troughs or two crests and the Frequency is defined as the number of cycles that pass through a point per second

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3 years ago

Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth.What is the acc

garri49 [273]

Answer:

(a). The acceleration due to gravity at the surface of Titania is 0.37 m/s².

(b). The average density of Titania is 1656.47 kg/m³

Explanation:

Given that,

Radius of Titania $R_{t}= \dfrac{1}{8}R_{e}$