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AleksandrR [38]
1 year ago
10

Factor 169-4d^2 and identify the perfect square

Mathematics
1 answer:
nexus9112 [7]1 year ago
4 0

By definition, a Perfect square is a number that is the square of an Integer.

In this case, you have the following expression given in the exercise:

169-4d^2

You can identify that:

169=13\cdot13=13^2

Therefore, it is a Perfect square.

Notice that:

4d^2=(2d)^2

Therefore, it is a Perfect square.

For this case you must apply the Difference of two squares is:

a^2-b^2=(a+b)(a-b)

Then, you can factor the expression:

=-(2d-13)(2d+13)

The answers are:

- Factored expression:

-(2d-13)(2d+13)

- ´Perfect squares:

\begin{gathered} 169=13^2 \\ 4d^2=(2d)^2 \end{gathered}

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STEP BY STEP EXPLINATION


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HOPE THIS HELPS! HAVE A GREAT DAY!
8 0
2 years ago
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Im not sure what to do here or how to start for AP calculus
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What’s the question ?
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