Question

Factor 169-4d^2 and identify the perfect square

Answer 1

By definition, a Perfect square is a number that is the square of an Integer.

In this case, you have the following expression given in the exercise:

$169-4d^2$

You can identify that:

$169=13\cdot13=13^2$

Therefore, it is a Perfect square.

Notice that:

$4d^2=(2d)^2$

Therefore, it is a Perfect square.

For this case you must apply the Difference of two squares is:

$a^2-b^2=(a+b)(a-b)$

Then, you can factor the expression:

$=-(2d-13)(2d+13)$

The answers are:

- Factored expression:

$-(2d-13)(2d+13)$

- ´Perfect squares:

$\begin{gathered} 169=13^2 \\ 4d^2=(2d)^2 \end{gathered}$