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Finger [1]
3 years ago
5

5431 - 3413 = 2018 2022 2028

Mathematics
1 answer:
Alborosie3 years ago
4 0
The Answer to your question is 2018
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You can mow 2 acres of your field in an hour and
alekssr [168]

Answer: I think the answer is 8hrs and 30 minuets

8 0
3 years ago
The length of a rectangular garden is 6 more than its width. If the perimeter is 32 feet, what is the width and the area of the
PolarNik [594]

Answer:

{\fbox{ \sf{Width \: of \: a \: rectangular \: garden \:  = 5 \: feet}}}

\boxed{ \sf{ \: Area \: of \: a \: rectangular \: garden = 55 {ft}^{2}}}

Step-by-step explanation:

\star Let the width of a rectangular garden be 'w'

\star Length of a rectangular garden = 6 + w

\star Perimeter of a rectangular garden = 32 feet

<u>\longrightarrow</u><u> </u><u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u> :

\boxed{ \sf{ \: Perimeter \: of \: a \: rectangle \:  =  \: 2(length + width}}

\mapsto{ \text{32 = 2(6 + w + w)}}

\text{Step \: 1 \:  : Collect \: like \: terms}

Like terms are those which have the same base

\mapsto{ \text{32 = 2(6 + 2w) }}

\text{Step \: 2 \:  : Distribute \: 2 \: through \: the \: parentheses}

\mapsto{ \text{32 = 12 + 4w}}

\text{Step \: 3 \:  : Swap \: the \: sides \: of \: the \: equation}

\mapsto{ \text{4w + 12 = 32}}

\text{Step \: 4 \:  : Move \: 12 \: to \: right \: hand \: side \: and \: change \: its \: sign}

\mapsto{ \text{4w = 32 - 12}}

\text{Step \: 5 \:  : Subtract \: 12 \: from \: 32}

\mapsto{ \sf{4w = 20}}

\text{Step \: 6 \:  : Divide \: both \: sides \: by \: 4}

\mapsto{ \sf{ \frac{4w}{4}  =  \frac{20}{4}}}

\text{Step \: 7 \:  : Calculate}

\mapsto{ \text{w = 5}}

Width of a rectangular garden = 5 feet

\longrightarrow <u>Substituting </u><u>/</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>w </u><u>in </u><u>6</u><u> </u><u>+</u><u> </u><u>w </u><u>in </u><u>order </u><u>to </u><u>find</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular </u><u>garden</u>

\mapsto{ \sf{Length = 6 + w = 6 + 5 =  \bold{11 \: feet} }}

\longrightarrow <u>Finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having</u> <u>length of 11 feet and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>feet</u> :

\boxed{ \sf{Area \: of \: a \: rectangle = length \:∗ \:  width}}

\mapsto{ \text{Area \:  =  \: 11 \: ∗ \:   5}}

\mapsto{ \sf{Area \:  = 55 \:  {ft}^{2} }}

Area of a rectangular garden = 55 ft²

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

6 0
2 years ago
4//2 and 20/6 are these numbers proportions?
goblinko [34]
They are not the same as proportions
4 0
3 years ago
Find the slope given the points (3,18) and (0,18).
docker41 [41]

Answer:

0

Step-by-step explanation:

Slope is calculated y2-y1/x2-x1

18-18/0-3

0/-3

0

8 0
3 years ago
What is the most common factor between 139 and 100
posledela

Answer:

1

Step-by-step explanation:

The common factors are:

1

The Greatest Common Factor:

GCF = 1

Solution

Teh factors of 100 are:

1, 2, 4, 5, 10, 20, 25, 50, 100

Teh factors of 139 are:

1, 139

The common factors are:

1

The Greatest Common Factor:

GCF = 1

3 0
3 years ago
Read 2 more answers
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