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Naily [24]
3 years ago
6

Plsss i need help boys and girls lol FRL :)

Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0
Seems to be D would be correct
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The sum of a number, n, and a number 5 is larger than it is 41. Which of the following equations could be used to solve for the
Allisa [31]
The answer is A hope this helps
5 0
2 years ago
Three consecutive odd integers have a sum of 3.what are the number
lapo4ka [179]
X = smallest odd
x + 2 = second odd
x + 4 = third odd

x + x + 2 + x + 4 = 3
3x + 6 = 3
3x = -3
x = -1

The numbers are -1, 1, 3. Hope this helps!
6 0
3 years ago
Read the instructions
nordsb [41]

Answer:

Step-by-step explanation:

\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}

Multiply the equation by 4

4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

5x = 6y + 4

5x - 6y = 4 --------------------(I)

\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\

Multiply the equation by 6

6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\

2*(7y + 3) = 3x + 2*7

14y + 6 = 3x + 14

14y = 3x + 14 - 6

14y = 3x + 8

-3x + 14y = 8 ------------------------(II)

Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3              15x - 18y = 12

(II)*5           <u>-15x  + 70y = 40</u>     {Now add}

                          52y = 52

                              y = 52/52

                            y = 1

Substitute y =1 in equation (I)

5x - 6*1 =  4

5x - 6 = 4

      5x = 4 +6

      5x = 10

         x = 10/5

x = 2

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3 years ago
Marco can swim at a speed of 45
diamong [38]
I hope this helps you

4 0
2 years ago
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Find a rational zero of the polynomial function and use it to find all the zeros of the function. f(x) = x4 + 3x3 - 5x2 - 9x - 2
olchik [2.2K]
Polynomials in the fourth degree are called quartic equations. In solving the roots of polynomials, there are techniques available. For quadratic equations, you use the quadratic formula. For cubic equations, you use the scientific calculator. But for quartic equations and higher, it is very complex. The method is very lengthy and can get very messy because you introduce a lot variables. So, I suggest you do the easiest method to estimate the roots.

Graph the equation by plotting arbitrary points. The graph looks like that in the figure. The points at which the curve passes the x-axis are the solution which are encircled in red.In approximation, the rational roots or zero's are -3.73, -1, -0.28 and 2.

3 0
3 years ago
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