Ask question

Ask question

All categories

11 months ago

12

A laptop has a listed price of $699.99 before tax. If the sales tax rate is 6.75%, find the total cost of the laptop with sales

tax included. Round your answer to the nearest cent, as necessary. HELP PLS I WILL GIVE BRAINLIEST!!!

1 answer:

Nookie1986 [14]11 months ago

4 0

The total cost of the laptop with sales tax included is to the nearest cents is 747.24 dollars.

<h3>What is sales tax?</h3>

A sales tax is a consumption tax imposed by the government on the sale of goods and services

In other words, sales tax is an amount of money, calculated as a percentage, that is added to the cost of a product or service when purchased by a consumer at a retail

A laptop has a listed price of $699.99 before tax.

The sales tax rate is 6.75%.

Total cost of the laptop with sales tax included can be calculated as follows:

sale tax = 6.75% of 699.99

sale tax = 6.75 / 100 × 699.99

sale tax = 4724.9325 / 100

sale tax = 47.249325 dollars

Therefore,

Total cost of the laptop with sales tax included = 47.249325 + 699.99 = 747.239325 dollars = 747.24 dollars.

learn more on sales tax here: brainly.com/question/17236543

#SPJ1

You might be interested in

Solve for y: 5y = 9 1/2

valkas [14]

Answer:

1 9/10

Step-by-step explanation:

I was first make me brainliest. :)

3 0

2 years ago

Read 2 more answers

**Spam answers will not be tolerated**

Morgarella [4.7K]

Answer:

$f'(x)=-\frac{2}{x^\frac{3}{2}}$

Step-by-step explanation:

So we have the function:

$f(x)=\frac{4}{\sqrt x}$

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

$\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Therefore, our derivative would be:

$\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}$

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

$=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}$

Place the 4 in front:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}$

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})$

Distribute:

$=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}$

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

$=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }$

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

$= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}$

The numerator will use the difference of two squares. Thus:

$=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Simplify the numerator:

$=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Both the numerator and denominator have a h. Cancel them:

$=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Now, substitute 0 for h. So:

$=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})$

Simplify:

$=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})$

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

$=4( \frac{-1}{(x)(2\sqrt{x})})$

Multiply across:

$= \frac{-4}{(2x\sqrt{x})}$

Reduce. Change √x to x^(1/2). So:

$=-\frac{2}{x(x^{\frac{1}{2}})}$

Add the exponents:

$=-\frac{2}{x^\frac{3}{2}}$

And we're done!

$f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}$

5 0

2 years ago

x+2y+2z=3. 2x-2y-z=3. x-2z=-5

d1i1m1o1n [39]

Answer:

x = 1, y = -2, z = 3.

Step-by-step explanation:

x + 2y + 2z = 3 A

2x -2y - z = 3 B

x - 2z = -5 C

If we add equations A and B we eliminate y:

3x + z = 6 E

Multiply E by 2 :

6x + 2z = 12 F

Adding C and F we get:

7x = 7

x = 1.

Plug this into equaton C:

1 - 2z = -5

-2z = -5 - 1 = -6

z = 3.

Now plugging x = 1 and z = 3 in equation A:

1 + 2y + 2(3) = 3

2y = 3 - 1 - 6 = -4

y = -2.

8 0

2 years ago

I need help answering this question please & thank you

belka [17]

The answer is secant.

3 0

2 years ago

If f(x)=5x-2 and g(x)=2x+1, find (f+g)(x)<br> A.7x-3 <br> B.3x-1 <br> C.7x-1 <br> D.4x-3

Gwar [14]

Answer:

(f+g)(x) = 7x -1 (Answer C)

Step-by-step explanation:

Rewrite these two functions, one above the other, for ease in adding:

f(x) = 5x - 2

+g(x) =2x + 1

------------------

(f+g)(x) = 7x -1

6 0

2 years ago