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melomori [17]
3 years ago
13

Which of the following expressions is this one equivalent to?

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}

Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

Factoring again in the numerator with common factor x^{3}+1:

\frac{(x^{3}+1)(x-2)}{x^{3}+1}

Simplifying:

x-2

Hence, the correct option is C. x-2

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The product of a number and 7, decreased by the number is equal to 42. find the number.
lozanna [386]
Let the number be x.
7x-x=42
6x=42
x=7
the number is 7
7 0
3 years ago
Two numbers that add to -4 and multiply to -45.
cricket20 [7]

Answer:

-9 and 5 make -4 and -45

Step-by-step explanation:

-9 and 5 make -4 and -45

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Jessica went to the grocery store and purchased a box of cereal for $3.75, milk for $1.50, and bread for $2.25. She paid with a
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Answer:

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Step-by-step explanation:

3 0
3 years ago
What is the missing fraction for 1/6 1/8 1/4 ?/? = 1whole
denis23 [38]
The answer is 11/24.

5 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
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