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melomori [17]
3 years ago
13

Which of the following expressions is this one equivalent to?

Mathematics
1 answer:
schepotkina [342]3 years ago
3 0

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}

Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

Factoring again in the numerator with common factor x^{3}+1:

\frac{(x^{3}+1)(x-2)}{x^{3}+1}

Simplifying:

x-2

Hence, the correct option is C. x-2

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Anwser: 28 :) 35 DEVIDED BY 5 IS 7 AND 7 X 4 IS 28
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If f (x) = 6x - 6, find f(-1).
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Step-by-step explanation:

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

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1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
Please give me the correct answer.Only answer if you're very good at math.Please use the Pythagorean Theorem formula which is a^
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Answer:

c = 8.7 inches

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multiply 4.8 times itself, 7.3 times itself:

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2 years ago
Convert (20 possible points)
Sergeeva-Olga [200]

Answer:

9.7*10^9 or 9,700,000,000

Step-by-step explanation:

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9.7 * 10^6 * 1000 = 9.7*10^9 or 9,700,000,000

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8 0
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