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2 years ago

Which of the following expressions is this one equivalent to?

Mathematics

1 answer:

schepotkina [342]2 years ago

3 0

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

$\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}$

Factoring in the numerator:

$\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}$

Factoring again in the numerator with common factor $x^{3}+1$ :

$\frac{(x^{3}+1)(x-2)}{x^{3}+1}$

Simplifying:

$x-2$

Hence, the correct option is C. x-2

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The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (according to GolfWeek). Assume th

Usimov [2.4K]

Answer:

a) $f(x) = \frac{1}{25.9}$

b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

$P(X < x) = \frac{x - a}{b - a}$

The probability of finding a value between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The probability of finding a value above x is:

$P(X > x) = \frac{b - x}{b - a}$

The probability density function of the uniform distribution is:

$f(x) = \frac{1}{b-a}$

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.

This means that $a = 284.7, b = 310.6$ .

a. Give a mathematical expression for the probability density function of driving distance.

$f(x) = \frac{1}{b-a} = \frac{1}{310.6-284.7} = \frac{1}{25.9}$

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

$P(X < 290) = \frac{290 - 284.7}{310.6-284.7} = 0.2046$

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

3 0

2 years ago

What is the approximate distance from the origin to the point (3, −4, 5)? Round to the nearest unit. 4 units 7 units 8 units 9 u

Dafna11 [192]

Answer:

Option B is correct.

Step-by-step explanation:

The distance formula used is:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}$

We need to find distance between origin and other point (3,-4,5)

Origin is: (0,0,0)

x₁ = 0, y₁ = 0, z₁ =0 and x₂= 3, y₂= -4 and z₂ = 5

Putting values in the distance formula we get:

$d=\sqrt{(3-0)^2+(-4+0)^2+(5-0)^2}\\d=\sqrt{(3)^2+(-4)^2+(5)^2}\\d=\sqrt{9+16+25}\\d=\sqrt{50}\\d=7$

The Distance from the origin to the point (3, −4, 5) is 7 units.

Option B is correct.

3 0

3 years ago

5x+7/2=3/2x-14 solve this

Alchen [17]

X=-2

You can also check by plugging -2 in for x. Here is a picture. Please notify me if I made an error!

3 0

3 years ago

SALE

RUDIKE [14]

Answer:

$15

Step-by-step explanation:

60x75%

60x0.75

60-45=15

5 0

2 years ago

Lf R(x) = x2 – 3x – 1, find R(-2). a.9 b.-9 c.-3 d.-11

fenix001 [56]

Answer:

Step-by-step explanation:

If R(-2), then x = -2. Just plug in -2 for x. -2^2 - 3(-2) - 1 = 4 + 6 - 1 = 10 - 1 = 9. The answer is 9.

6 0

2 years ago