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3 years ago

What is the property of 7/9 * 1 = 7/9

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

Answer:

Identity property of multiplication (multiplying a number by one will result in that number)

Step-by-step explanation:

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Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.

DiKsa [7]

Answer:

The arc length of the entire circle would be 2*PI*9

We need to know the arc length of 1/3 of the circle so we calculate

arc length = (2 * PI * 9) / 3

arc length = 2 * PI * 3

arc length = 6 * PI

arc length = 18.8495559215

Step-by-step explanation:

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3 years ago

I'll give brainliest to whoever answers the question correctly!!

yulyashka [42]

Answer:

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2 years ago

Sum of three consecutive natural numbers is 63, what is the greatest number?

nalin [4]

Answer:

19, 21 and 23 are the three consecutive odd numbers which give 63 when adding these numbers.

Step-by-step explanation:

6 0

3 years ago

"If two polygons are similar, then their corresponding angles are equal in measure." True or false?

egoroff_w [7]

Answer:

true hope it helps thanks

7 0

3 years ago

Read 2 more answers

The probability that a student correctly answers on the first try (the event

Mademuasel [1]

Note that the two events are mutually exclusive. If the question is answered correctly on the first try, there's no need to give it another attempt. So $\mathbb P(A\cap B)=0$ .

We're given that $P(A)=0.2$ and $P(B\mid A^C)=0.5$ . From the first probability, we know that $P(A^C)=1-0.2=0.8$ . By definition of conditional probability,

$\mathbb P(B\mid A^C)=\dfrac{\mathbb P(B\cap A^C)}{\mathbb P(A^C)}$
$\implies\mathbb P(B\cap A^C)=0.5\cdot0.8=0.4$

We're interested in the probability of either $A$ or $B$ occurring, i.e. $\mathbb P(A\cup B)$ . Apply the inclusion-exclusion principle, which says

$\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)$

We know the probability of intersection is 0, and we know $\mathbb P(A)$ . Meanwhile, by the law of total probability, we have

$\mathbb P(B)=\mathbb P(B\cap A)+\mathbb P(B\cap A^C)=\mathbb P(B\cap A^C)$

so we end up with

$\mathbb P(A\cup B)=0.2+0.4=0.6$

3 0

3 years ago