Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Answer:
Multiply all the numbers and you will get your answer. It is 483 cm^3
Hope this helped, have an awesome day and please mark brainliest if u want too.
1.
a.) 2q + 5r
2(7) + 5(-2)
14 - 10 = 4
b.) 3(p + 6) + q + r Plug in the numbers
3(5 + 6) + 7 - 2 Solve inside the parentheses first
3(11) + 7 - 2
33 + 5 = 38
2.
a.) m(3m + 4n)
2(3(2) + 4(3))
2(6 + 12)
2(18) = 36
b.) n²(m + p²)
(3)²(2 + (-5)²)
9(2 + 25)
9(27) = 243
c.) 3m(8 + n) + n²
3(2) (8 + 3) + 3²
6(11) + 9
66 + 9 = 75
Answer:
Distributive Property of Multiplication
Answer:
A) 10
Step-by-step explanation:
In the US, a number in scientific notation will have a mantissa (a) such that ...
1 ≤ a < 10
That is, the value of "a" must be between 1 and 10 (not including 10).
_____
<em>Comment on alternatives</em>
In other places or in particular applications (some computer programming languages), the standard form of the number may be a×10^n with ...
0.1 ≤ a < 1
In engineering use, the form of the number is often chosen so that "n" is a multiple of 3, and "a" is in the range ...
1 ≤ a < 1000
This makes it easier to identify and use the appropriate standard SI prefix: nano-, micro-, milli-, kilo-, mega-, giga-, and so on.
