Answer:
4
Step-by-step explanation:
X=7
no i think
acute
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Answer:
i would say (B) or (C) but ill go with (C)
Step-by-step explanation:
Answer:
Rotate Figure L 135 degrees counterclockwise around the point of intersection of the arms. Reflect across the right arm
Step-by-step explanation:
Answer:
a) We can calculate the mean with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X= \frac{350+ 70+ 65 +50+ 60}{5} =119](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B350%2B%2070%2B%2065%20%2B50%2B%2060%7D%7B5%7D%20%3D119)
And for the median first we need to order the dataset on increasing way:
50, 60, 65, 70, 350
Since the sample size is an odd number we can calculate the median as the middle position for the dataset, for this case the 3th position and we got:
Median = 65
b) For this case we can see that we have an outlier present in the data 350, and for this case if we want to give a measure of central tendency is better use the median since this meaure is not affected by outliers. So Lauren should use the median.
Step-by-step explanation:
For this case we have the following data:
350, 70, 65, 50, 60
Part a
We can calculate the mean with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X= \frac{350+ 70+ 65 +50+ 60}{5} =119](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B350%2B%2070%2B%2065%20%2B50%2B%2060%7D%7B5%7D%20%3D119)
And for the median first we need to order the dataset on increasing way:
50, 60, 65, 70, 350
Since the sample size is an odd number we can calculate the median as the middle position for the dataset, for this case the 3th position and we got:
Median = 65
Part b
For this case we can see that we have an outlier present in the data 350, and for this case if we want to give a measure of central tendency is better use the median since this meaure is not affected by outliers. So Lauren should use the median.