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4 years ago

A raincoat costs $79.25 today. If a similar raincoat cost $52.48 in 1983, what is the CPI? a. 166 b. 151 c. 132 d. 127

Mathematics

2 answers:

Ugo [173]4 years ago

8 0

Answer:

Option b. 151

Step-by-step explanation:

A raincoat costs $79.25 today. If a similar raincoat cost $52.48 in 1983 then we have to calculate the the CPI in 1983.

Since formula to calculate CPI will be

CPI = (Price of raincoat today/Price of raincoat in 1983)×100

CPI = 79.25×100/52.48 = 151

Therefore option b. CPI = 151 is the answer.

tamaranim1 [39]4 years ago

4 0

B. You divide 79.25/52.48 and get 1.51, which translates to 151 percent.

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Deffense [45]

Answer:

$H( - 2) = - 7 \frac{1}{5}$

Step-by-step explanation:

We want to evaluate the equation

$H(y) = \frac{9}{5} \times 2y$

at y=-2

We just have to substitute to obtain;

$H( - 2) = \frac{9}{5} \times 2 \times - 2$

We now multiply to get:

$H( - 2) = \frac{9}{5} \times - 4$

This is the same as:

$H( - 2) = \frac{9}{5} \times \frac{ - 4}{1}$

We multiply the numerators separately and denominators separately to get:

$H( - 2) = \frac{9 \times - 4}{5 \times 1}$

$H( - 2) = \frac{ - 36}{5}$

This implies that

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3 years ago

During a bike challenge riders have to collect various colored ribbons each half mile they collect a red ribbon each 8th mile th

soldi70 [24.7K]

Answer:

Green and Blue ribbon

Step-by-step explanation:

Given

They collect

Red Ribbon = ½ mile

Green Ribbon = ⅛ mile

Blue Ribbon = ¼ mile

To find?

Which colors of ribbons will be collected at the ¾ mile mark.

The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.

Testing each fraction.

Red Ribbon = ½

¾ ÷ ½

= ¾ * 2

= 3/2

= 1.5 or 1 Remainder 1

This is not an exact multiple of ¾. So, the red ribbon won't be passed here.

Green Ribbon = ⅛

¾ ÷ ⅛

= ¾ * 8

= 24/8

= 3

This is an exact multiple of ¾. So, the green ribbon will be collected.

Testing the last ribbon

Blue = ¼

¾ ÷ ¼

= ¾ * 4

= 3

This is an exact multiple of ¾. So, the blue ribbon will be collected.

Hence, the green and blue ribbons will be collected at ¾ mile mark

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3 years ago

Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv

uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(more than 4.25 minutes to solve a problem)

$P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%$

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

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3 years ago

The ratio of boys to girls in Ella’s grade is 3 to 4. The ratio of boys to girls in Minh’s grade is 4 to 5. Each grade has a tot

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Answer:

In mih's school there are 100 boys

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Step-by-step explanation:

X*1/5=20

X=100

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3 years ago

In a horse race, how many different finishes among the first 3 places are possible if 7 horses are running? (Exclude ties)

kodGreya [7K]

Answer:

7 x 6 x 5 = 210

Step-by-step explanation:

its a combination's problem.

7 horses are eligible for first place.

6 of those are eligible for 2nd given that one of the 7 finished first.

similarly 5 of the remaining are eligible for 3rd place given 2 horses have taken the first 2 spots.

therefore 7 x 6 x 5 possible combinations = 210 combinations.

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3 years ago