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Anni [7]
1 year ago
6

How would a clinician actually apply epithelial absorption techniques

Physics
1 answer:
Bond [772]1 year ago
8 0

A clinician actually apply epithelial absorption techniques through the following below:

  • Oral meds.
  • Inhalation
  • Injections

<h3>What is Epithelial absorption?</h3>

This is referred to as the process which is responsible for the absorption of various types of nutrients from the intestinal lumen and transporting them across the epithelium by various organs in the body such as the kidney etc to the blood vessels such as capillaries.

The various ways in which a a clinician would actually apply the epithelial absorption techniques is through oral meds like in the case of water and electrolytes and also in the case injections via insulin shots etc.

Read more about Epithelium here brainly.com/question/27960196

#SPJ1

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What is charging by conduction. <br> Can you also give an real life example of it.
Vadim26 [7]

Answer: Where the charged object is brought near but never contacted to the object being charged, conduction charging involves making the physical connection of the charged object to the neutral object. Because charging by conduction involves contact, it is often called charging by contact.

Real life example: A positively charged aluminum plate comes into contact with a neutral metal sphere

Explanation:

3 0
3 years ago
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A water wave has a wavelength of 204 m and a frequency of 0.5 Hz. How far does it travel in 1 s?
Zigmanuir [339]

Answer:

c = 204 x 5 = 1020 m/s so it travels 1020 meters in 1 second.

Explanation:

7 0
2 years ago
Light enters air from water. The angle of refraction will be A. less than the angle of incidence. B. greater than or equal to th
Rina8888 [55]

Answer:

E. greater than the angle of incidence.

Explanation:

Snell's law states that:

n_i sin \theta_i = n_r sin \theta_r (1)

where

n_i, n_r are the refractive index of the first and second medium

\theta_i, \theta_r are the angle of incidence and refraction, respectively

For light moving from water to air, we have:

n_i = 1.33 (index of refraction of water)

n_r = 1.00 (index of refraction of air)

Substituting into (1) and re-arranging the equation, we get

\sin \theta_r = \frac{n_i}{n_r} sin \theta_i = 1.33 sin \theta_i

which means that

\theta_r > \theta_i

so, the correct answer is

E. greater than the angle of incidence.

4 0
3 years ago
Read 2 more answers
Electrons in a particle beam each have a kinetic energy of 4.0 × 10 −17 J. What is the magnitude of the electric field that will
Dmitry_Shevchenko [17]

Answer:

-833.3 N/C

Explanation:

Kinetic energy, K, in terms of electric field, E, is given as:

K = qEr

q = charge = e = 1.6 × 10⁻¹⁹C

E = Electric field

r = distance = 0.3m

The electric field can be gotten by making E subject of formula:

E = K/(qr)

The electeic field needed to stop the electrons must be equal in magnitude to the electric field carried by these electrons:

E = (4.0 × 10⁻¹⁷)/(-1.6 × 10⁻¹⁹ * 0.3)

E = -833.3 N/C

This is the electric field needed to stop the electrons.

The negative sign means that the electric field must be in a direction opposite to the motion of the electrons.

3 0
3 years ago
Read 2 more answers
A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falli
trapecia [35]

The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

  • mass of the toy, m = 0.1 kg
  • the maximum height reached by the, h = 0.45 m

The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

7 0
2 years ago
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