Answer:
V1 = 2221.33 L
Explanation:
The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:
(1)
And also for the situation in which the variables T, V and P has changed:
(1)
R: constant of ideal gases = 0.082 L.atm/mol.K
For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):
![n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BP_1V_1%7D%7BRT_1%7D%5C%5C%5C%5Cn%3D%5Cfrac%7BP_2V_2%7D%7BRT_2%7D)
Next, you equal these equations an solve for T2:
![\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BRT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BRT_2%7D%5C%5C%5C%5CV_1%3D%5Cfrac%7BP_2V_2T_1%7D%7BP_1T_2%7D)
Finally you replace the values of P2, V2, T1 and T2:
![V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7B%287atm%29%28680L%29%28140%5C%C2%B0C%29%7D%7B%2860%5C%C2%B0C%29%285atm%29%7D%3D2221.33%5C%20L)
Hence, the initial volume of the gas is 2221.33 L
Hearing test provides an evaluation of the sensitivity of a person's sense of hearing and is most often performed by an audiologist using an audiometer. An audiometer is used to determine a person's hearing sensitivity at different frequencies.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete because of the absence of options but when you slam on the brakes when riding a bike or other vehicles, the bike undergoes deceleration. Deceleration is a type of acceleration with a negative value which usually points in the opposite direction of the velocity. As described in the question, deceleration is usually brought about by a decrease in magnitude of a velocity.
Answer:
The heat change of the system is 30 J.
Explanation:
Given;
increase in internal energy of a system, ΔU = 80 J
work done on the system, W = 50 J
The heat change of the system can be calculated from first law of Thermodynamics;
ΔU = Q - W
where;
Q is the heat absorbed by the system
W is the work done by the system (negative when work is done by the system and positive when work is done on the system)
Since work was done on the system the increase internal energy is given as;
ΔU = Q + W
ΔU - W = Q
80 J - 50 J = Q
30 J = Q
Therefore, the heat change of the system is 30 J.