<span>a) 3 bulbs rated 40W for 5 hrs : 3*40*5 = 600 Watt hours
</span><span>b) A heater rated 1500W for 3hrs 3* 1500 = 4500 Watt hours
</span>
<span>c) A fridge rated 400W
Would assume the Fridge would run for 24 hours a day :400*24 = 9600 Watt hours
</span>
Total Watt hours for 1 day :
600 + 4500 + 9600 = 14700 Watt hours
Unit of Electricity is in kWh
14 700 wh = 14700/1000 = 14.7kWh
But 1kWh = Rs.3
14.7 kWh = 3*14.7 = 44.1
Total cost = Rs.44.10
Answer:
Explanation:
<u>Work
</u>
The work done by an external force F when moving an object by a distance X parallel to its direction is
The second Newton's law gives us the net force acting on an object of mass m which is being moved at an acceleration a:
Replacing the last equation into the first equation
And solving for a
There seems to be some kind of mistake in the data provided, we'll use it anyway
It's a very small value as compared to the dimensions of the rest of the problem.
<span>it either changes the direction of the object or it stops the object in motion.</span>
Question:
In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller is 6.00 m, and, while being driven into rotation around a fixed axis, its angular position is expressed as θ = 2.70t² − 0.900t3³
where θ is in radians and t is in seconds.
(a) Find the maximum angular speed of the roller.
(b) What is the maximum tangential speed of a point on the rim of the roller?
(c) At what time t should the driving force be removed from the roller so that the roller does not reverse its direction of rotation?
(d) Through how many rotations has the roller turned between t = 0 and the time found in part (c)?
Answer:
a. 2.7rad/s
b. 8.1 m/s
c. 2 s
d. 3.6 rad
Explanation:
Answer:
Temperature T2 = 237.5 K
Explanation:
Given:
Volume = 35 ml
T1 = 285 k
P1 = 150 pa
P2 = 125 pa
Find:
Temperature T2
Computation:
P1V/T1 = P2V/T2
150(35) / 285 = 125(35) / T2
Temperature T2 = 237.5 K