What is the place value of9 in 8.00231497?

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

ANSWER

Ten-millionths

EXPLANATION

We want to find the place value of 9 in 8.00231497.

The number 9 is placed 7 places beyond the decimal point. This implies that its value is 7 orders of 10 less than 8 and its place value is ten-millionths.

That is the answer.

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mars1129 [50]

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When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.

For our functions, the compositions are:

u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2

w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8

Now we evaluate each composition at 4.

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5 0

3 years ago

What error did zacharias make? the –5 should be 5. the 52 should be –52. the 2 in the numerator should be –2. the 2 in the denom

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