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DanielleElmas [232]
3 years ago
15

A production line at vj sugumaran's machine shop has three stations. The first station can process a unit in 10 minutes. The sec

ond has two identical machines , each of which can process a unit in 12 minutes( each unit only needs to be processed one one of two machines). The third station can process a unit in 8 minutes. Which station is the bottleneck station?

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

See it in the pic

Step-by-step explanation:

See it in the pic

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Estimate -9 1/6+2 1/3+(-1 7/8)
Eduardwww [97]

Answer:

-9

Step-by-step explanation:

-9+2-2=-9

5 0
3 years ago
- 6x +15 <br>Can anyone please show me the steps of solving this equation​
Vesna [10]

Answer:

-6x + 15 = - 69 which x = 14

Step-by-step explanation:

You cannot solve this equation. There is no equal sign anywhere. Either you mean

-6x = 15 in which case the answer is

-6x/-6 = 15/-6

x = - 2 1/2 or x= - 2.5

or you mean that you use the distributive property

- 3(2x + 5)

You may have left something out of this.

-6x + 15 = -  69

You can do it now that you have the complete equation. But you need the entire equation before you can answer the question.

Subtract - 15 from both sides.

-6x + 15 - 15 = -69 - 15

-6x = - 84

Divide by - 6

-6x/-6 = - 84/-6

x = 14

But what you want is

-6x + 15

-6*14 + 15

-84 + 15

-69

-6x + 15 = - 69

when x = 14 which is usually what you are asked.

5 0
3 years ago
Over winter break, Raymond worked 12.5 hours at the library and 20.5 hours at a café. The library paid him $13 per hour. If he e
svet-max [94.6K]

Answer:

14.5

Step-by-step explanation:

the cafe paid him 14.5 an hr

6 0
3 years ago
What is the 4(4x)+(x) equal!?
e-lub [12.9K]

4(4x)+(x)

= 16x+x

Combine like terms

16x+x

(16x+x)

= 17x

x=17


I hope that's help ! Good night .

5 0
3 years ago
Socks cost $5 per pair.
Morgarella [4.7K]

Answer:

because there is no cents, so its a whole number, and it will help if u put the answer choices

Step-by-step explanation:

8 0
2 years ago
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