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PilotLPTM [1.2K]
1 year ago
15

What is the image point of (-5,0) after a translation left 2 units and down 1 unit? Submit Answer attempt 1 out of 2

Mathematics
1 answer:
anygoal [31]1 year ago
7 0

If you want to translate a point (x,y) to the left, you have to subtract the number of units (n) that you want to translate it from the original x coordinate, like this:

(x-u,y)

And if you want to translate a point (x,y) downwards, just subtract the number of units n you want to translate from the y coordinate, like this:

(x,y-n)

in this case, we have the point (-5,0) which image would be:

After a translation of 2 to the left

and with 1 unit down, this point would look like this:

(-5-2,0-1)=(-7,-1)

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Lady bird [3.3K]

Answer:

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Step-by-step explanation:

Data provided in the question:

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Now,

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differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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