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In-s [12.5K]
3 years ago
7

Write and solve an equation to find the value of each variable

Mathematics
1 answer:
yan [13]3 years ago
3 0
Check the picture below.

as you can see in the picture, the "near arc" is x°, and the "far arc", is the leftover from subtracting the arc of 120° and x°, therefore then

\bf 44=\cfrac{\stackrel{far~arc}{(360-x-120)~~-~~\stackrel{near~arc}{x}}}{2}\implies 88=240-2x
\\\\\\
2x=152\implies x=\cfrac{152}{2}\implies x=76

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2 years ago
An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24
melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}

z = -0.68

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

7 0
2 years ago
Solve for c: a=7b+8c+9d-10
polet [3.4K]
<span>a=7b+8c+9d-10
a = 8c + 16d - 10
solve for c then
8c = a - 16d + 10
  c = (</span>a - 16d + 10) / 8
or
  c = a/8 - 2d + 5/4
7 0
3 years ago
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