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ivann1987 [24]
11 months ago
6

Y varies directly as xy equals 5 when X is 8 how do you find y when X is 9

Mathematics
1 answer:
FrozenT [24]11 months ago
5 0

Given, y varies directly as x

So,

y=c\cdot x

Where c is a constant

When y equals 5 when x is 8

So,

\begin{gathered} 5=c\cdot8 \\ c=\frac{5}{8} \\  \end{gathered}

So, the relation between y and x

y=\frac{5}{8}x

now , when x = 9

Substitute with x to find y

y=\frac{5}{8}\cdot9=\frac{45}{8}

So, the answer is option 2. y = 45/8

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