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3 years ago

(x2 + 4)(x2 - 4) please answer it

Mathematics

1 answer:

kotegsom [21]3 years ago

8 0

Answer:

x^4-16

Step-by-step explanation:

This is only right if you just want to multiply them together.

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Write a multiplication equation that has a solution of 12. Use tape diagrams to prove that your equation has a solution of 12.

natima [27]

Answer:

The required equation is 3y=36 and the tape diagram is shown below.

Step-by-step explanation:

Consider the provided information.

We need to write a multiplication equation that has a solution of 12.

3y=36

We know we have to split 36 into three equal groups, so we have to divide by 3 to show this algebraically.

3y÷3=36÷3

y=12

Now check this with the help of tape diagram as shown.

Consider the figure 1.

This represents if 36 had to be split into three groups, how big would each group be?

By the tape diagram we concluded that the value of y is 12.

5 0

3 years ago

If F (x) =8+11 X-3X², find<br> a. What is F (5)? <br> b. What is F (x + b)? <br> c. What is F (-3)?

stepladder [879]

Answer:

a) -12

b) 8+11x+11b-3x^2-3b^2-6xb

c)-52

Step-by-step explanation:

in a) we have to substitute the value of x with 5

in b) we substitute the value of x with (x+b) and then simplify

in c) just have to substitute x with -3

5 0

2 years ago

Fill in the blanks so that the resulting statement is true. If f is a polynomial function and f(a) and f(b) have opposite sig

tia_tia [17]

Answer:

f(c) equals zero

Intermediate Value Theorem

Step-by-step explanation:

Intermediate value theorem is one which states that f is a continuous function whose domain contains intervals which are a and b. It takes on any value between f(a) and f(b) at some point within interval. If we know the two values, we can pick any number between those two values and determine its function.

6 0

3 years ago

58.5ft <br>area is rug of an 10 to 12 feet floor.what area is not rug.

jenyasd209 [6]

The answer is 61.5

Please mark as brainliest; have a blessed day!

5 0

3 years ago

Read 2 more answers

Let a1, a2, a3, ... be a sequence of positive integers in arithmetic progression with common difference

Bezzdna [24]

Since $a_1,a_2,a_3,\cdots$ are in arithmetic progression,

$a_2 = a_1 + 2$

$a_3 = a_2 + 2 = a_1 + 2\cdot2$

$a_4 = a_3+2 = a_1+3\cdot2$

$\cdots \implies a_n = a_1 + 2(n-1)$

and since $b_1,b_2,b_3,\cdots$ are in geometric progression,

$b_2 = 2b_1$

$b_3=2b_2 = 2^2 b_1$

$b_4=2b_3=2^3b_1$

$\cdots\implies b_n=2^{n-1}b_1$

Recall that

$\displaystyle \sum_{k=1}^n 1 = \underbrace{1+1+1+\cdots+1}_{n\,\rm times} = n$

$\displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2$

It follows that

$a_1 + a_2 + \cdots + a_n = \displaystyle \sum_{k=1}^n (a_1 + 2(k-1)) \\\\ ~~~~~~~~ = a_1 \sum_{k=1}^n 1 + 2 \sum_{k=1}^n (k-1) \\\\ ~~~~~~~~ = a_1 n + n(n-1)$