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lesya692 [45]
3 years ago
12

Find the median of the table below. Number of inches 20,22,24,26. Frequency 3,2,1,3. ​

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

23

Step-by-step explanation:

20,22,24,26

(22+24)/2 = 23

Hope this helps my bad if its wrong

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What is the equation of the line that passes through the point (6, 4) and has a slope<br> of - ?
Dafna1 [17]
Hey what’s the slope ?
4 0
3 years ago
Solve the system of equations -4x-2y=30−4x−2y=30 and -x+y=6−x+y=6 by combining the equations.elimination
oee [108]

Answer:

215.00

Step-by-step explanation:

5 0
3 years ago
What is the surface area of the box if it is scaled up by the factor of 10 and the surface area is 16in
algol [13]
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.

Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be

New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600

Final Answer: 1600 square inches

3 0
3 years ago
Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv
mojhsa [17]

Answer:

The inequality to show how many hours of television Julia can still watch this week can be given as:

⇒ x+1.5\leq 5

where x represents he number of hours of television that Julia can still watch this week

On solving for x, we get

x\leq3.5

Thus, Julia can still watch no more than 3.5 hours of television this week.

Step-by-step explanation:

Given:

Julia is allowed to watch television no more than 5 hours a week.

She has already watched 1.5 hours

To write and solve an inequality to show how many hours of television Julia can still watch this week.

Solution:

Let the number of hours of television that Julia can still watch this week be = x

Number of hours already watched = 1.5

Total number of hours of watching television this week would be given as:

⇒ x+1.5

It is given that Julia is allowed to watch no more than 5 hours of television in a week.

Thus, the inequality can be given as:

⇒ x+1.5\leq 5

Solving for x

Subtracting both sides by 1.5

x+1.5-1.5\leq 5-1.5

x\leq3.5

Thus, Julia can still watch no more than 3.5 hours of television this week.

6 0
3 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
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