The infant should be given a trial of bronchodilators.
Explanation:
Bronchodilators are compounds that dilates the bronchioles and smoothens the flow of air through them.
The infant has gonorrhea and cough. This shows that he has excessive mucus secretion in his respiratory tract.
Wheezing and prolonged expiration shows that the infant is having breathing difficulty.
Wheezing usually occurs when there is a blockage in the bronchial passage.
Since immunizations are up to date, chances of probable infections are less.
In this case the physician should use a bronchodilator trial to check if the blockage in the bronchus is due to mucus.
Then any further examination should be followed.
Red blood cells- these cells help in carrying of oxygen in the body
white blood cells- these cells ward of infection in the body
platelets- platelets assist in blood clotting
Water or other molecules move down their concentration gradient without any energy.........
difference - simple diffusion uses help of transporting protein in the membrane whereas osmosis uses no help.
Answer:
Explanation:
1.
Cathepsin is involved in programmed cell death, it is a lysosomal enzyme and the reason it is found in the ER fraction instead of the lysosomal fraction is because of its c terminal KDEL sequence. this sequence ia a retrieval for protein and causes a backward movement of protein back to endoplasmic reticulum. that is why cathepsin seems to have localised in ER instead of the lysosomal fraction
2 It does not bind to mannose-6-phosohate receptor because this glycosylation process does not occur in the E.R but in Golgi bodies. because of the KDEL sequence this glycosylation of cathepsin would not occur and cathepsin would go through affinity column without any form of binding to receptor.If cathepsin can get to the Golgi then glycolysation with Mannose6phospate can occur.
