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1 year ago

Help me please. Your the best if you help.

Mathematics

1 answer:

ASHA 777 [7]1 year ago

4 0

Answer: x = 25, y=15, z = 58

Step-by-step explanation:

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brilliants [131]

Answer:

1. 100 which Is the easier one

2. 5

5 0

3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

I need some assistance

motikmotik

I think B I'm not sure but if I think it's B, if it is not, let me know.

8 0

3 years ago

Suppose the lengths, in seconds, of the songs in an online database are normally distributed. For a random sample of songs, the

sattari [20]

Answer:

186

Step-by-step explanation:

The sample mean, x, is the central value in the confidence interval, that is, the average between the upper and lower bounds of the interval.

In this case, the Lower bound is 184.00 and the upper bound is 188.00. Therefore, the sample mean is given by:

$x = \frac{184+188}{2}\\x=186.00$

The mean length, in seconds, of the sampled songs is 186.00.

5 0

3 years ago

SOMEONE HELP ME PLEASE

vlada-n [284]

Answer:

Total Cost = 29x + 0.32y

Step-by-step explanation:

It is 29x since you pay $29 per day, and x represents the number of days.

It is 0.32y since you pay $0.32 per mile, and y represents the number of miles.

5 0

3 years ago