I don’t know how to do this.

Mathematics

1 answer:

In-s [12.5K]2 years ago

5 0

Step-by-step explanation:

THIS IS THE RIGHT ANSWER PLEASE BRAINLIEST ME PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE

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3 6/12 rounded to the nearest whole number

oee [108]

Answer:

Step-by-step explanation:

6/12= .5

3.5≈4

4 0

3 years ago

A large pipe dispenses 750 gallons of water in 50 seconds .at this rate how long will it take to dispense 330 gallons

Leya [2.2K]

<h2><em>750 gallons of water flows through the pipe in = 50 seconds. </em></h2><h2><em>350 gallons of water will flow in =50/750 x 330= = </em><u><em>22 seconds.</em></u></h2>

7 0

3 years ago

Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44

tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}$

then,Let

P1(33,-22)

P2(52,-33)

replace,

$\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}$

Step 2

find the equation of the line

$y-y_1=slope(x-x_1)\rightarrow equation$

let

$\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}$

replace,

$\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}$

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

$\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}$

so, the x intercetp is -5.

I hope this helps you