Question

AB. CD. EF are three chords of a circle, P and Q are two points inside the circle such that AB and CD meet at P, and AB and EF meet at Q. If CP = 2, PD = 7, EQ = 3, QF = 6 and
AP = 2, then QB may be
A. 2 B. 3 C. 4 D. 5 E. 7​

Answer 1

Answer:

Step-by-step explanation:

I think it is option E) 7