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2 years ago

If f(x)=6x^2-4 what is f(-1)

Mathematics

1 answer:

Nana76 [90]2 years ago

3 0

Answer:

Step-by-step explanation:

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Need help on this please giving brainlest! :)

denis23 [38]

Answer:

a) (-4, 5)

b) (4, -5)

Step-by-step explanation:

Just reverse the signs or use desmos as a better example.

6 0

3 years ago

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Hi can you help me with this?

katrin [286]

Answer:

-3.9/1

Step-by-step explanation:

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3 years ago

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If −20 is the 15th term in an arithmetic sequence with a common difference of −7, what is the first term in the sequence?

Sphinxa [80]

An=A1+(n-1)d
-20=A1+(15-1)x-7
-20=A1+14 x -7
-20=A1-98
+98 +98
-98+98=0
-20+98=78
A1=78

8 0

3 years ago

The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu

zavuch27 [327]

Answer:

The center of the circle is at;

$(1,-3)$

The radius of the circle is;

$r=4$

Explanation:

Given the equation of circle;

$x^2+y^2-2x+6y-6=0$

we want to re-write it in the form;

$(x-h)^2+(y-k)^2=r^2$

where;

$\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}$

Applying Completing the square method;

$\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}$

comparing the derived equation to the general form we have;

$\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}$

Therefore;

The center of the circle is at;

$(1,-3)$

The radius of the circle is;

$r=4$

6 0

11 months ago

State the hypothesis and claim:

vekshin1

Answer:

Null Hypothesis: H₀ : μ < 214 miles

Alternative Hypothesis :H₁: μ> 214 miles

The calculated value |t| = 1.319 < 3.4966 at 0.01 level of significance

Null hypothesis is accepted

The average daily travel distance is less than 214 miles

Step-by-step explanation:

Step(i):-

Given that the size of the sample 'n' = 12

The mean of the Population = 214 miles

The mean of the sample = 198 miles

The standard deviation of the sample = 42 miles

Level of significance = 0.01

Step(ii):-

Null Hypothesis: H₀ : μ < 214 miles

Alternative Hypothesis :H₁: μ> 214 miles

Test statistic

$t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$t = \frac{198 -214}{\frac{42}{\sqrt{12} } }$

|t| = |- 1.319| = 1.319

Degrees of freedom = n-1 = 12 -1 =11

critical value $t_{(0.005 , 11)} = 3.4966$

The calculated value |t| = 1.319 < 3.4966 at 0.01 level of significance

Null hypothesis is accepted

The average daily travel distance is less than 214 miles

3 0

3 years ago