Answer:
C
Step-by-step explanation:
The maximum/minimum values is simply the y-value of the vertex. Since both of the functions have a negative leading coefficient, they will both have maximum values.
For Function 1, we can see that the vertex is at (4,1). Thus, it's maximum value is at y=1.
For Function 2, we need to work out the vertex. To do this we can use:
To find the vertex.
Function 2 is defined by:
Therefore:
Thus, the vertex of Function 2 is at (2,5). Therefore, the maximum value of Function 2 is y=5.
5 is greater than 1, so the maximum value of Function 2 is greater.
The answer is choice C.
Area = 1/4√(5(5+2√5))a^2. a is the length of a side. If you plug in 10 as a, you get approximately 172, which is about the same as the 1st option .
He should have added 1 to both sides to make the -1 on the right go to 0.
Then it would be 0 + m = -16 + 1 = -15
You can check your work by adding -1 and -15, which does in fact equal -16.
Hope this helped :)
Answer is B.
We see the center lines are 80 and 85 as stated.
A is wrong because the range of class 2 is less.
C is wrong; class 2 has a minimum of 50
D is wrong; class 2 has a smaller interquartile range, which is the width of the boxes.
In expanded form :
100,000+10,000+4,000+6
