X basketball players who tried out for the team were chosen. They were distributed into 5 groups each. In one of the groups, 2 of the teammates left. How many players did that group have?
I'm sure you can word this even better.. I'm just in a rush.
Answer:
(x, y) = (-3, 2)
Step-by-step explanation:
Put the given value of y into the equation and solve for x.
... 7·2 +3x = 5
... 3x = -9 . . . . . . subtract 14
... x = -3 . . . . . . . divide by the x-coefficient
The solution (x, y) is (-3, 2).
25x/45=-65
25x=2925
x=117
I wasn't sure if you wanted a solution
For every c substitute 4 and for every d substitute -2
c=4
d=-2
6c + 5d - 4c - 3d + 3c - 6d
= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)
=24+(-10)-16-(-6)+12-(-12)
=24-10-16+6+12+12
=28
If 80% are women, then 20% are men
20% of what equals 880
0.20x = 880
x = 880/.20
x = 4400
check..
men : 20% of 4400 = 0.20(400) = 880
women : 80% of 4400 = 0.80(4400) = 3520
totaling : 3520 + 880 = 4400
so there are a total of 4400 workers
