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Ksivusya [100]
10 months ago
14

Me podrían ayudar a contestar estas preguntas, por favorspeak spanish

Mathematics
1 answer:
lisabon 2012 [21]10 months ago
7 0

En un parallelogramo, los lados opuestos son paralelos. De la misma forma, los angulos opuestos son iguales y los angulos adjacentes suman 180 grados.

Con ello, podemos decir que:

a. Los lados RS y UT son paralelos.

b. Los lados RU y ST son paralelos.

c. El angulo en U es igual al angulo en S pues son opuestos

d. Los angulos en S y T son adjacentes . Esto quiere decir que, su suma es igual a 180 grados.

e. El angulo en R es igual al angulo en T pues son opuestos.

f. De forma similar al caso d, los angulos U y R son adjacentes, su suma es 180 grados.

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Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}

Where :

m = mass of the oebjct in motion

m_o = mass of the object when at rest

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We have :

1) Mass of the Dave = m_o=66 kg

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = m_o=66 kg

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}

v=2.973\times 10^8 m/s

Dave should be moving at speed of 2.973\times 10^8 m/s.

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LongSong = 286s

LongSong = 2 * ShortSong - 126s

=>

2 * ShortSong - 126s = 286s

2 * ShortSong = 286s + 126s

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