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6 months ago

Me podrían ayudar a contestar estas preguntas, por favorspeak spanish

Mathematics

1 answer:

lisabon 2012 [21]6 months ago

7 0

En un parallelogramo, los lados opuestos son paralelos. De la misma forma, los angulos opuestos son iguales y los angulos adjacentes suman 180 grados.

Con ello, podemos decir que:

a. Los lados RS y UT son paralelos.

b. Los lados RU y ST son paralelos.

c. El angulo en U es igual al angulo en S pues son opuestos

d. Los angulos en S y T son adjacentes . Esto quiere decir que, su suma es igual a 180 grados.

e. El angulo en R es igual al angulo en T pues son opuestos.

f. De forma similar al caso d, los angulos U y R son adjacentes, su suma es 180 grados.

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nikdorinn [45]

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uranmaximum [27]

Answer:

acceleration=force/mass

Due to variation in the mass[ as same force as per magnitude acts on both of them] the acceleration developed in the bug will be more and the acceleration developed in the car is negligible.

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The impulse of bug is more and that of car is small.

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Step-by-step explanation:

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3 years ago

Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

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a. Differentiating the Taylor series gives

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$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

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and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

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c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

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lutik1710 [3]

Answer:

Step-by-step explanation:

The answer is 18794.86549

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