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Nat2105 [25]
3 years ago
5

Jack is 1.75 m tall and casts a shadow 2.25 m long. At the same time, a statue casts a shadow 9 m long. What is the height of th

e statue?
a. 4 m
b. 7 m
c.5.75 m
d.11.6 m
Mathematics
2 answers:
iren2701 [21]3 years ago
8 0

Answer:

b. 7 m

Step-by-step explanation:

There is a direct proportion relationship between the length of the object/person and the shadow cast by it.

Let the length of the object/person be L an that of the shadow be B

L ∝ B

L = KB

where K is the constant of proportionality.

Where L = 1.75 m, B = 2.25 m

1.75 = 2.25B

B = 175/225 = 7/9

Therefore, L = (7/9)B

If at the same time, a statue casts a shadow 9 m long, then B = 9 m

L = (7/9) × 9

L = 7 m

The height of the statue is 7 m.

Arisa [49]3 years ago
5 0
7m
1.75 divided by 2.25 = 0.77777777...
0.77777777.. times by 9 = 7
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Given △MON≅△PQR with MO=20 , MN=32 and PR=3x−10. Find the value of x.<br><br> show your work
aliya0001 [1]

Answer:

x=14

Step-by-step explanation:

we know that

If two figures are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

△MON≅△PQR

so

corresponding sides

MO≅PQ

MN≅PR

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corresponding angles

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∠O≅∠Q

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3 years ago
Connie's dog fido weighs 35 pounds. Her vet placed fido on a diet. What inequality can you write to find the average number of p
lawyer [7]

Fido's dog must lose 1.17 pounds each month to reach healthier weight.

Step-by-step explanation:

Given,

Weight of fido's dog = 35 pounds

Time period = 6 months

Goal weight to reach = 28 or less pounds

Let,

m be the weight to be lose each month.

Weight of dog - Time period * Weight to lose each month ≤ Goal weight

35-6m\leq 28\\-6m\leq 28-35\\-6m\leq -7

Dividing both sides by -6

\frac{-6m}{-6}\leq \frac{-7}{-6}\\\\m\leq 1.17

Fido's dog must lose 1.17 pounds each month to reach healthier weight.

Keywords: division, subtraction

Learn more about division at:

  • brainly.com/question/10382470
  • brainly.com/question/10382722

#LearnwithBrainly

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Step-by-step explanation:

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tan 30 = opposite / adjacent

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